How to instantiate an object tied to java enum

I want to instantiate object for an enum. For example:

public enum Type {

  TYPE1("type_name_1", new TypeObj1()), 
  TYPE2("type_name_2", new TypeObj2());

  TypeInterface typeObj;
  String value;
}

public class TypeObj1 implements TypeInterface {
  ...
}

public class TypeObj2 implements TypeInterface {
  ...
}

Is this a correct way to do it? I want a single object of TypeInterface attached to enum. Please suggest alternatives.

Yes, you are headed in the right direction.

You’ll need a constructor to assign the passed objects to your member fields.

Make your member fields final to prevent their reassignment to another object reference.

public enum Type {
  // Enum objects.
  TYPE1("type_name_1", new TypeObj1()), 
  TYPE2("type_name_2", new TypeObj2());

  // Member fields.
  final TypeInterface typeObj;
  final String value;

  // Constructor.
  Type( final String value , final TypeInterface typeInterface ) {
    this.typeObj = typeInterface ;
    this.value = value ;
  }
}

Tip: This kind of thought exercise is more clear and productive if you devise a simple but semi-realistic scenario rather than your amorphous “TypeInterface” and “value”.

public enum Pet {
  // Enum objects.
  FLUFFY( "tuxedo" , new Cat() ), 
  ROVER( "chocolate Lab" , new Dog() );
  
  // Member fields.
  final Animal animal;
  final String description;

  // Constructor.
  Type( final String desc , final Animal animal ) {
    this.animal = animal ;
    this.description = desc ;
  }
}

Create a constructor for your enum, which matches the arguments you're specifying.
There is no access-modifier; and private is redundant.

Enum Types (The Java™ Tutorials > Learning the Java Language > Classes and Objects).

public enum Type {
    TYPE1("type_name_1", new TypeObj1()),
    TYPE2("type_name_2", new TypeObj2());

    final TypeInterface typeObj;
    final String value;
    
    Type(String value, TypeInterface typeObj) {
        this.value = value;
        this.typeObj = typeObj;
    }
}