英文:
Shell Script Eliminate full path while creating zip
问题
我有一个目录路径 /root/Archive/EKS/data - 在这个 data 文件夹下有一些文本文件，我的目标是需要将整个 data 目录压缩，并将压缩文件保留在相同的位置 (/root/Archive/EKS/data)。
但是下面的脚本在我们预期的情况下工作，但是当我解压缩文件夹时，文件夹路径从 /root/Archive/EKS/data 开始重复，但我不想根据完整路径创建压缩文件，而是希望基于 data 目录创建压缩文件。
└─# tree root/
root/
└── Archive
└── EKS
└── validate-file
3 directories, 0 files
startdir=(
"/root/Archive/EKS/data"
)
for dir in "${startdir[@]}" ; do
for sub_dir in "$dir"/*/ ; do
zip "${sub_dir%/}.zip" "$sub_dir"
done
done
你能指导我在哪里出错吗？
英文:
I have directory path /root/Archive/EKS/data - Under this data folder I have some text file, my goal is need take entire data directory and keep the zipped file into same place (/root/Archive/EKS/data.
But the below is script is working as we expected but when I'm doing unzipping the folder path start from /root/Archive/EKS/data, its repeating but I don't want to make zip based on full path instead it needs to create zip file based on data directory only.
└─# tree root/
root/
└── Archive
└── EKS
└── validate-file
3 directories, 0 files
startdir=(
"/root/Archive/EKS/data"
)
for dir in "${startdir[@]}" ; do
for sub_dir in "$dir"/*/ ; do
zip "${sub_dir%/}".zip "$sub_dir"
done
done
can you please guide me where I'm missing it.
答案1
得分: 2
你可以这样做：
#!/bin/bash
startdir="/root/Archive/EKS/data"
cd "$startdir" || exit
for sub_dir in */ ; do
zip -r "${sub_dir%/}.zip" "$sub_dir"
done
cd $startdir 命令将工作目录更改为/root/Archive/EKS/data。
然后，我们遍历data目录中的每个子目录（*/），并创建zip文件。
希望有所帮助。
英文:
You can do something like this
#!/bin/bash
startdir="/root/Archive/EKS/data"
cd "$startdir" || exit
for sub_dir in */ ; do
zip -r "${sub_dir%/}.zip" "$sub_dir"
done
cd $startdir command changes the working directory to /root/Archive/EKS/data.
Then we iterate through each subdirectory (*/) within the data directory and create the zip file.
hope it helps.
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