如何在dio库中以表单主体发送未来的列表

huangapple
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英文:

How do I send future list in form body in dio library

问题

你好，我已经为您翻译了代码部分，如下所示：

  1. Future<void> setData(List<ModelOrder>) async {
  2.   var formData = FormData.fromMap({
  3.     'UserId': ModelOrder.userId,
  4.     'ProductId': ModelOrder.productId,
  5.     'quantity': ModelOrder.quantity,
  6.     'productPrice': ModelOrder.price,
  7.     'paymentMethod': ModelOrder.paymentMethod,
  8.   });
  9.   try {
  10.     String url = "example.com/api";
  12.     final response = await Dio().post(url, data: formData);
  14.     if (response.data == "success") {
  15.       print("this is success insert of order");
  16.     } else {
  17.       print('fail to insert order');
  18.     }
  19.   } catch (e) {
  20.     print(e.toString());
  21.   }
  22. }

希望这对您有帮助。如果您有任何其他问题，请随时提问。

英文:

Hello Guy I have tried to send the flutter list but now I am only able to send one by one data. I am trying to send list through dio here what I have tried

  1.  Future&lt;void&gt; setData(List&lt;ModelOrder&gt;) async 
  2.        {
  3.     
  4.         var formData = FormData.fromMap({
  5.                   
  6.                       &#39;UserId&#39;: ModelOrder.userId,
  7.                       &#39;ProductId&#39;: ModelOrder.productId, 
  8.                       &#39;quantity&#39;: ModelOrder.quantity, 
  9.                       &#39;productPrice&#39;: ModelOrder.price,
  10.                       &#39;paymentMethod&#39;: ModelOrder.paymentMethod,
  11.                      
  12.                 });
  13.         try{
  14.             String url = &quot;example.com/api&quot;;
  15.     
  16.             final response = await Dio().post(url,data: formData,);
  17.     
  18.            
  19.             if(response.data == &quot;success&quot;){
  20.              print(&quot;this is success insert of order&quot;);
  21.             } 
  22.             else{
  23.               print(&#39;fail to insert order&#39;);
  24.     
  25.             }
  26.            
  27.     
  28.         }
  29.         catch(e){
  30.           print(e.toString());
  31.         }
  32.     
  33.         
  34.       }

答案1

得分: 0

我认为，你不能使用form-data类型作为请求体来发布列表。

尝试这样做。

  1. Future<void> setData(List<ModelOrder> data) async {
  2.   String url = "example.com/api";
  3.   var params = data.map((e) {
  4.     return {
  5.       'UserId': e.userId,
  6.       'ProductId': e.productId,
  7.       'quantity': e.quantity,
  8.       'productPrice': e.price,
  9.       'paymentMethod': e.paymentMethod,
  10.     };
  11.   });
  13.   try {
  14.     final response = await Dio().post(
  15.       url,
  16.       data: params,
  17.     );
  19.     if (response.data == "success") {
  20.       print("this is success insert of order");
  21.     } else {
  22.       print('fail to insert order');
  23.     }
  24.   } catch (e) {}
  25. }

注意：上述代码是Dart语言的示例代码，用于将列表数据发送到指定的URL。

英文:

I think, you cant post list using form-data type as a body.

try this.

<!-- begin snippet: js hide: false console: true babel: false -->

<!-- language: lang-js -->

  1. Future &lt;void&gt; setData(List&lt;ModelOrder&gt; data) async {
  2.   String url = &quot;example.com/api&quot;;
  3.   var params = data.map((e) {
  4.     return {
  5.       &#39;UserId&#39;: e.userId,
  6.       &#39;ProductId&#39;: e.productId,
  7.       &#39;quantity&#39;: e.quantity,
  8.       &#39;productPrice&#39;: e.price,
  9.       &#39;paymentMethod&#39;: e.paymentMethod,
  10.     };
  11.   });
  13.   try {
  14.     final response = await Dio().post(
  15.       url,
  16.       data: params,
  17.     );
  19.     if (response.data == &quot;success&quot;) {
  20.       print(&quot;this is success insert of order&quot;);
  21.     } else {
  22.       print(&#39;fail to insert order&#39;);
  23.     }
  24.   } catch (e) {}
  25. }

<!-- end snippet -->

huangapple
  • 本文由 发表于 2023年5月24日 22:24:57
  • 转载请务必保留本文链接：https://go.coder-hub.com/76324599.html
  • dart
  • dio
  • flutter
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