英文:
C++ Windows Winsock SChannel - AcquireCredentialsHandleW failing - due to UNISP_NAME or SChannel?
问题
我正在尝试在 Windows 中使用 winsock、schannel、security 等,在 C++ x64 unicode 中实现 SSL 握手。示例主机是 google.com。
我创建了一个 SOCKET,并且可以通过 WSAConnectByNameW 连接。
我设置了我的 SCHANNEL 参数如下:
SCHANNEL_CRED *cred = new SCHANNEL_CRED;
cred->dwVersion = SCHANNEL_CRED_VERSION;
cred->dwFlags = SCH_USE_STRONG_CRYPTO | SCH_CRED_AUTO_CRED_VALIDATION | SCH_CRED_NO_DEFAULT_CREDS;
cred->grbitEnabledProtocols = SP_PROT_TLS1_2;
我想要使用 AcquireCredentialsHandleW(传递 UNISP_NAME)获取句柄:
SECURITY_STATUS secstatus = AcquireCredentialsHandleW(NULL, UNISP_NAME, SECPKG_CRED_OUTBOUND, NULL, &cred, NULL, NULL, &handle, NULL);
由于不兼容的数据类型,这会失败:
""const wchar_t *"" --> ""LPWSTR"""
顺便说一下,这里的 Handle 只是一个 CredHandle。
我正在使用 Unicode,所以我认为我可以使用 UNISP_NAME,因为它是一个以 0 结尾的字符串。
我尝试将字符串转换为 LPWSTR。这只是指向以 0 结尾字符串的指针,对吧?
std::wstring service = L"Microsoft Unified Security Protocol Provider";
LPWSTR servicePtr = &service[0];
然后将其传递给函数:
SECURITY_STATUS secstatus = AcquireCredentialsHandleW(NULL, servicePtr, SECPKG_CRED_OUTBOUND, NULL, &cred, NULL, NULL, &handle, NULL);
但似乎不起作用。我不明白。我的问题是什么?
为什么我无法获取句柄?为什么函数(AcquireCredentialsHandleW)即使在正确的编码中也不接受其自己的预编码参数?
提前感谢。
PS:我想尽量不使用 OpenSSL 或 Curl 进行尝试 ^^
尝试切换到多字节编码。相同的问题,但不是针对 wchar,而是 char。
尝试将字符串转换为指针
尝试使用不同编码的 schannel 参数。
英文:
I'm trying to implement an SSL handshake in C++ x64 unicode in Windows using winsock, schannel, security etc. Example host is google.com.
I created a SOCKET and could connect via WSAConnectByNameW.
I'm setting my SCHANNEL parameters as followed:
SCHANNEL_CRED *cred = new SCHANNEL_CRED;
cred->dwVersion = SCHANNEL_CRED_VERSION;
cred->dwFlags = SCH_USE_STRONG_CRYPTO | SCH_CRED_AUTO_CRED_VALIDATION| SCH_CRED_NO_DEFAULT_CREDS;
cred->grbitEnabledProtocols = SP_PROT_TLS1_2;
I want to get the handle using AcquireCredentialsHandleW (passing UNISP_NAME):
SECURITY_STATUS secstatus = AcquireCredentialsHandleW(NULL, UNISP_NAME, SECPKG_CRED_OUTBOUND, NULL, &cred, NULL, NULL, &handle, NULL);
Which fails for some reason due to incompatible data types:
> ""const wchar_t *"" --> ""LPWSTR""
Btw. Handle is just a CredHandle here.
I'm using unicode so I thought I could use UNISP_NAME since it's a 0 terminated string.
I tried converting the string into an LPWSTR. Which is just an pointer to a 0 terminated string, right?
std::wstring service = L"Microsoft Unified Security Protocol Provider";
LPWSTR servicePtr = &service[0];
And pass it to the function:
SECURITY_STATUS secstatus = AcquireCredentialsHandleW(NULL, servicePtr, SECPKG_CRED_OUTBOUND, NULL, &cred, NULL, NULL, &handle, NULL);
But it doesn't seem to work. I don't get it. What's my problem here?
Why can't I get the handle? Why does the function (AcquireCredentialsHandleW) does not accept its own pre-coded parameters even in the correct encoding?
Thanks in advance.
PS.: I want to try it without openssl or curl as far as I can make it ^^
Tried switching to multibyte. Same problem but not for wchar but chars.
Tried converting the string to a pointer
tried switching schannel parameter with differently encoded parameter.
答案1
得分: 0
AcquireCredentialsHandle()
的第二个参数期望一个指向非const字符串的指针(为什么是非const?谁知道)。
UNISP_NAME
只是一个字符串字面量的#define
:
#define UNISP_NAME_A "Microsoft Unified Security Protocol Provider"
#define UNISP_NAME_W L"Microsoft Unified Security Protocol Provider"
#ifdef UNICODE
#define UNISP_NAME UNISP_NAME_W
...
#else
#define UNISP_NAME UNISP_NAME_A
...
#endif
在C++中,字符串字面量是const字符串(在这种情况下是const wchar_t[]
,它退化为const wchar_t*
)。
所以,在C++中,你需要去掉const
,例如:
AcquireCredentialsHandleW(..., const_cast<LPWSTR>(UNISP_NAME), ...);
或者,你可以使用字符串字面量来初始化一个非const字符缓冲区,例如:
WCHAR szPackage[] = UNISP_NAME;
AcquireCredentialsHandleW(..., szPackage, ...);
在C++11及更高版本中,你的wstring::operator[]
方法应该能够正常工作,因为std::wstring
的内部内存缓冲区保证是以空字符结尾的,例如:
std::wstring package = UNISP_NAME_W;
AcquireCredentialsHandleW(..., &package[0], ...);
或者,你可以从wstring::c_str()
返回的指针中去掉const
,例如:
std::wstring package = UNISP_NAME_W;
AcquireCredentialsHandleW(..., const_cast<LPWSTR>(package.c_str()), ...);
或者,在C++17及更高版本中,wstring::data()
有一个重载,可以返回一个非const指针,例如:
std::wstring package = UNISP_NAME_W;
AcquireCredentialsHandleW(..., package.data(), ...);
英文:
The second parameter of AcquireCredentialsHandle()
expects a pointer to a non-const string (why non-const? who knows).
UNISP_NAME
is just a #define
for a string literal:
#define UNISP_NAME_A "Microsoft Unified Security Protocol Provider"
#define UNISP_NAME_W L"Microsoft Unified Security Protocol Provider"
#ifdef UNICODE
#define UNISP_NAME UNISP_NAME_W
...
#else
#define UNISP_NAME UNISP_NAME_A
...
#endif
In C++, a string literal is a const string (in this case, a const wchar_t[]
, which decays into a const wchar_t*
).
So, you will have to cast away the const
in C++, eg:
AcquireCredentialsHandleW(..., const_cast<LPWSTR>(UNISP_NAME), ...);
Alternatively, you can use a string literal to initialize a non-const character buffer, eg:
WCHAR szPackage[] = UNISP_NAME;
AcquireCredentialsHandleW(..., szPackage, ...);
Your wstring::operator[]
approach should work fine in C++11 and later, where the internal memory buffer of std::wstring
is guaranteed to be null-terminated, eg:
std::wstring package = UNISP_NAME_W;
AcquireCredentialsHandleW(..., &package[0], ...);
Or, you can cast away the const
from the pointer returned by wstring::c_str()
, eg:
std::wstring package = UNISP_NAME_W;
AcquireCredentialsHandleW(..., const_cast<LPWSTR>(package.c_str()), ...);
Or, in C++17 and later, wstring::data()
has an overload to return a non-const pointer, eg:
std::wstring package = UNISP_NAME_W;
AcquireCredentialsHandleW(..., package.data(), ...);
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