在Elasticsearch中查询聚合桶以获取唯一的术语集。

huangapple
go评论88阅读模式
英文:

Query aggregation buckets for unique sets of terms in Elasticsearch

问题

Here's the translated code portion:

  1. 给定以下索引：
  2. PUT /example
  3. {
  4.   "mappings": {
  5.     "properties": {
  6.       "tags": {
  7.         "type": "keyword"
  8.       }
  9.     }
  10.   }
  11. }
  13. POST example/_bulk
  14. { "create" : { "_index" : "example" } }
  15. { "tags" : ["a", "b"] }
  16. { "create" : { "_index" : "example" } }
  17. { "tags" : ["c", "d"] }
  18. { "create" : { "_index" : "example" } }
  19. { "tags" : ["e"] }
  20. { "create" : { "_index" : "example" } }
  21. { "tags" : ["c", "d"] }

And here's the translated response you're looking for:

  1. {
  2.   ...
  3.   "aggregations" : {
  4.     "tags" : {
  5.       "doc_count_error_upper_bound" : 0,
  6.       "sum_other_doc_count" : 0,
  7.       "buckets" : [                       
  8.         {
  9.           "key" : ["a", "b"],
  10.           "key_as_string" : "a|b",
  11.           "doc_count" : 1
  12.         },
  13.         {
  14.           "key" : ["c", "d"],
  15.           "key_as_string" : "c|d",
  16.           "doc_count" : 2
  17.         },
  18.         {
  19.           "key" : ["e"],
  20.           "key_as_string" : "e",
  21.           "doc_count" : 1
  22.         }
  23.       ]
  24.     }
  25.   }
  26. }

Please note that this translation includes only the requested code and response parts.

英文:

Given the following index:

  1. PUT /example
  2. {
  3.   "mappings": {
  4.     "properties": {
  5.       "tags": {
  6.         "type": "keyword"
  7.       }
  8.     }
  9.   }
  10. }
  12. POST example/_bulk
  13. { "create" : { "_index" : "example" } }
  14. { "tags" : ["a", "b"] }
  15. { "create" : { "_index" : "example" } }
  16. { "tags" : ["c", "d"] }
  17. { "create" : { "_index" : "example" } }
  18. { "tags" : ["e"] }
  19. { "create" : { "_index" : "example" } }
  20. { "tags" : ["c", "d"] }

I want to aggregate them by the unique set of tags, rather than by all documents that contain the tags. Similar to multi-terms aggregation, but looking at one field. So the response I'm looking for looks like this:

  1. {
  2.   ...
  3.   "aggregations" : {
  4.     "tags" : {
  5.       "doc_count_error_upper_bound" : 0,
  6.       "sum_other_doc_count" : 0,
  7.       "buckets" : [                       
  8.         {
  9.           "key" : ["a", "b"],
  10.           "key_as_string" : "a|b",
  11.           "doc_count" : 1
  12.         },
  13.         {
  14.           "key" : ["c", "d"],
  15.           "key_as_string" : "c|d",
  16.           "doc_count" : 2
  17.         },
  18.         {
  19.           "key" : ["e"],
  20.           "key_as_string" : "e",
  21.           "doc_count" : 1
  22.         }
  23.       ]
  24.     }
  25.   }
  26. }

I know one way to achieve this is to create another field that is a sorted string of all the tags and then do an aggregation on that field, but I just want to know if this is possible. My real use case is a little more complicated, using nested fields, so I'd like to avoid adding a new field.

答案1

得分: 1

尝试这个：

  1. PUT test_example
  2. {
  3.   "mappings": {
  4.     "properties": {
  5.       "tags": {
  6.         "type": "keyword"
  7.       }
  8.     }
  9.   }
  10. }
  12. POST _bulk?refresh
  13. { "create" : { "_index" : "test_example" } }
  14. { "tags" : ["a", "b"] }
  15. { "create" : { "_index" : "test_example" } }
  16. { "tags" : ["c", "d"] }
  17. { "create" : { "_index" : "test_example" } }
  18. { "tags" : ["e"] }
  19. { "create" : { "_index" : "test_example" } }
  20. { "tags" : ["c", "d"] }
  22. POST test_example/_search
  23. {
  24.   "size": 0,
  25.   "aggregations": {
  26.     "tags": {
  27.       "terms": {
  28.         "script": {
  29.           "source": "String.join('|', params._source.tags)",
  30.           "lang": "painless"
  31.         },
  32.         "collect_mode": "breadth_first",
  33.         "execution_hint": "map"
  34.       }
  35.     }
  36.   }
  37. }

如果您希望将 "c|d" 和 "d|c" 放在同一个桶中，您可以在搜索期间使用自定义脚本手动对标签进行排序。以下是更新后的查询：

  1. POST _bulk?refresh
  2. { "create" : { "_index" : "test_example2" } }
  3. { "tags" : ["c", "d"] }
  4. { "create" : { "_index" : "test_example2" } }
  5. { "tags" : ["d", "c"] }
  7. POST test_example2/_search
  8. {
  9.   "size": 0,
  10.   "aggregations": {
  11.     "tags": {
  12.       "terms": {
  13.         "script": {
  14.           "source": """
  15.             def sortedTags = params._source.tags.stream().sorted().collect(Collectors.toList());
  16.             String.join('|', sortedTags)
  17.           """,
  18.           "lang": "painless"
  19.         },
  20.         "collect_mode": "breadth_first",
  21.         "execution_hint": "map"
  22.       }
  23.     }
  24.   }
  25. }

在Elasticsearch中查询聚合桶以获取唯一的术语集。

编辑

如果您希望将 "c|d" 和 "d|c" 放在同一个桶中，您可以在搜索期间使用自定义脚本手动对标签进行排序。以下是更新后的查询：

  1. POST _bulk?refresh
  2. { "create" : { "_index" : "test_example2" } }
  3. { "tags" : ["c", "d"] }
  4. { "create" : { "_index" : "test_example2" } }
  5. { "tags" : ["d", "c"] }
  7. POST test_example2/_search
  8. {
  9.   "size": 0,
  10.   "aggregations": {
  11.     "tags": {
  12.       "terms": {
  13.         "script": {
  14.           "source": """
  15.             def sortedTags = params._source.tags.stream().sorted().collect(Collectors.toList());
  16.             String.join('|', sortedTags)
  17.           """,
  18.           "lang": "painless"
  19.         },
  20.         "collect_mode": "breadth_first",
  21.         "execution_hint": "map"
  22.       }
  23.     }
  24.   }
  25. }

在Elasticsearch中查询聚合桶以获取唯一的术语集。

英文:

try this:

  1. PUT test_example
  2. {
  3.   "mappings": {
  4.     "properties": {
  5.       "tags": {
  6.         "type": "keyword"
  7.       }
  8.     }
  9.   }
  10. }
  12. POST _bulk?refresh
  13. { "create" : { "_index" : "test_example" } }
  14. { "tags" : ["a", "b"] }
  15. { "create" : { "_index" : "test_example" } }
  16. { "tags" : ["c", "d"] }
  17. { "create" : { "_index" : "test_example" } }
  18. { "tags" : ["e"] }
  19. { "create" : { "_index" : "test_example" } }
  20. { "tags" : ["c", "d"] }
  22. POST test_example/_search
  23. {
  24.   "size": 0,
  25.   "aggregations": {
  26.     "tags": {
  27.       "terms": {
  28.         "script": {
  29.           "source": "String.join('|', params._source.tags)",
  30.           "lang": "painless"
  31.         },
  32.         "collect_mode": "breadth_first",
  33.         "execution_hint": "map"
  34.       }
  35.     }
  36.   }
  37. }

在Elasticsearch中查询聚合桶以获取唯一的术语集。

EDIT

If you want to keep "c|d" and "d|c" in the same bucket you can use a custom and you can sort the tags manually using a custom script during the search. Here's an updated query:

  1. POST _bulk?refresh
  2. { "create" : { "_index" : "test_example2" } }
  3. { "tags" : ["c", "d"] }
  4. { "create" : { "_index" : "test_example2" } }
  5. { "tags" : ["d", "c"] }
  7. POST test_example2/_search
  8. {
  9.   "size": 0,
  10.   "aggregations": {
  11.     "tags": {
  12.       "terms": {
  13.         "script": {
  14.           "source": """
  15.             def sortedTags = params._source.tags.stream().sorted().collect(Collectors.toList());
  16.             String.join('|', sortedTags)
  17.           """,
  18.           "lang": "painless"
  19.         },
  20.         "collect_mode": "breadth_first",
  21.         "execution_hint": "map"
  22.       }
  23.     }
  24.   }
  25. }

在Elasticsearch中查询聚合桶以获取唯一的术语集。

huangapple
  • 本文由 发表于 2023年5月24日 20:53:18
  • 转载请务必保留本文链接：https://go.coder-hub.com/76323766.html
  • elasticsearch
  • elasticsearch-aggregation
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定