SAS错误：检测到开放代码语句递归

huangapple
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英文:

SAS Error: Open Code Statement Recursion detected

问题

I am your Chinese translator, and I will only provide translations for the code portion you provided. Here's the translated code:

  1. 在以下代码中出现错误消息：
  3. %let start=1;
  4. %let end=6;
  6. %global i;
  7. %put 注意：&start, &end;
  9. /*打印 i*/
  10. %do i=&start %to &end;
  12. 	%put 注意：&i
  14. %end;
英文:

Just getting an error msg on the following code:

  1. %let start=1;
  2. %let end=6;
  4. %global i;
  5. %put note: &start, &end;
  7. /*Print i*/
  8. %do i=&start %to &end;
  10. 	%put note: &i
  12. %end;

答案1

得分: 1

你的循环中缺少一个分号：%put note: &i;。你还需要将循环封装在一个宏内。以下是修正后的代码：

  1. %macro loop;
  2.     %let start=1;
  3.     %let end=6;
  4.     
  5.     %global i;
  6.     %put note: &start, &end;
  7.     
  8.     /*打印i*/
  9.     %do i=&start %to &end; 
  10.     
  11.         %put note: &i;
  12.     
  13.     %end;
  14. %mend;
  15. %loop;
英文:

You're missing a semicolon in your loop: %put note: &i;. You also need to encapsulate your loop within a macro.

  1. %macro loop;
  2.     %let start=1;
  3.     %let end=6;
  4.     
  5.     %global i;
  6.     %put note: &start, &end;
  7.     
  8.     /*Print i*/
  9.     %do i=&start %to &end; 
  10.     
  11.         %put note: &i;
  12.     
  13.     %end;
  14. %mend;
  15. %loop;
  1. note: 1, 6
  2. note: 1
  3. note: 2
  4. note: 3
  5. note: 4
  6. note: 5
  7. note: 6

huangapple
  • 本文由 发表于 2023年5月23日 01:26:31
  • 转载请务必保留本文链接：https://go.coder-hub.com/76308614.html
  • macros
  • sas
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