英文:
Float matrix passed as a parameter to a function gives garbage values
问题
我想将一个 float 矩阵从主函数传递给另一个函数，代码如下所示：
#include <stdio.h>
// 在传递二维数组之前必须传递 n
void print(int m, int n, float arr[][n])
{
int i, j;
for (i = 0; i < m; i++)
for (j = 0; j < n; j++)
printf("%d ", arr[i][j]);
}
int main()
{
float arr[][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
int m = 3, n = 3;
print(m, n, arr);
}
这会输出：3 -1742458874 -1742458874 -1742458874 -1742458874 -1742458874 -1742458874 -1742458874 -1742458874
我尝试用 int 替换 float 作为数组的类型，这样做完全正常。我期望它与 float 一样工作，输出 "1 2 3 4 5 6 7 8 9"，但实际上它输出垃圾值。
英文:
I want to pass a float matrix to another function from the main function, the code being as follows:
#include <stdio.h>
// n must be passed before the 2D array
void print(int m, int n, float arr[][n])
{
int i, j;
for (i = 0; i < m; i++)
for (j = 0; j < n; j++)
printf("%d ", arr[i][j]);
}
int main()
{
float arr[][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
int m = 3, n = 3;
print(m, n, arr);
}
This gives the output: 3 -1742458874 -1742458874 -1742458874 -1742458874 -1742458874 -1742458874 -1742458874 -1742458874
I tried this by replacing float with int for the type of the array and it works perfectly fine. I expected it would work the same way with float, outputting "1 2 3 4 5 6 7 8 9" but instead it outputs garbage values.
答案1
得分: 1
%d 不适用于 float。使用 %f 应该解决问题，并且你应该看到预期的结果。如果你只想打印浮点数的“整数”部分，你也可以指定精度：
printf("%.0f ", arr[i][j]);
英文:
%d is the wrong format for floats. Using %f should solve the issue, and you should see the expected results. If you want to print only the "whole" part of the float, you can specify the precision too:
printf("%.0f ", arr[i][j]);
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