英文:
Incorporating optional arrays in case parsing stage
问题
以下是翻译好的内容：
以下的bash函数用于将项目填充到数组中。
语法是
multary OPTIONS ary1 ary2 ary3 "item1" "item2" marker "item3" marker "item4"
数组 `ary1`、`ary2` 和 `ary3` 是可选的。我想找到一种简化参数读取部分的方法，以便在处理位置参数的 `CASE` 部分中合并 `PART2` 中的数组解析代码。
multary ()
{
## 传递带有分隔符的多个数组。
## 分隔符作为分隔符
local dna="***" dnb="***"
while (( $# > 0 )); do
parg="$1"
case "$parg" in
("-m1") dna="$2" ; shift 2 ;;
("-m2") dnb="$2" ; shift 2 ;;
("--") shift 1 ; break ;;
(*) break ;;
esac
done
##====================================================
## PART2
if [[ "$(declare -p $1)" =~ "declare -a" ]]; then
typeset -n _ary1="$1"
_ary1=() ; shift 1
echo "_ary1 是一个数组"
fi
if [[ "$(declare -p $1)" =~ "declare -a" ]]; then
typeset -n _ary2="$1"
_ary2=() ; shift 1
echo "_ary2 是一个数组"
fi
if [[ "$(declare -p $1)" =~ "declare -a" ]]; then
typeset -n _ary3="$1"
_ary3=() ; shift 1
echo "_ary3 是一个数组"
fi
}
英文:
The following bash function fills items into arrays.
The syntax is
multary OPTIONS ary1 ary2 ary3 "item1" "item2" marker "item3" marker "item4"
The arrays ary1, ary2, ary3 are optional. I want to find a way to simplify the argument reading part so that the array parsing code in PART2 is incorporated in the CASE part for processing positional arguments.
multary ()
{
## Passing multiple arrays with marker between them.
## Marker as break
local dna="***" dnb="***"
while (( $# > 0 )); do
parg="$1"
case "$parg" in
("-m1") dna="$2" ; shift 2 ;;
("-m2") dnb="$2" ; shift 2 ;;
("--") shift 1 ; break ;;
(*) break ;;
esac
done
##====================================================
## PART2
if [[ "$(declare -p $1)" =~ "declare -a" ]]; then
typeset -n _ary1="$1"
_ary1=() ; shift 1
echo "_ary1 is an array"
fi
if [[ "$(declare -p $1)" =~ "declare -a" ]]; then
typeset -n _ary2="$1"
_ary2=() ; shift 1
echo "_ary2 is an array"
fi
if [[ "$(declare -p $1)" =~ "declare -a" ]]; then
typeset -n _ary3="$1"
_ary3=() ; shift 1
echo "_ary3 is an array"
fi
}
答案1
得分: 2
#!/usr/bin/env bash
multary(){
while (( $# > 0 )); do
case "$1" in
("-m") declare -n __ary="$2"; __ary=(); shift 2;;
(*) __ary+=("$1"); shift;;
esac
done
}
multary -m ary1 "item1" "item2" -m ary2 "item3" -m ary3 "item4"
declare -p ary1
declare -p ary2
declare -p ary3
# Output :
# declare -a ary1=([0]="item1" [1]="item2")
# declare -a ary2=([0]="item3")
# declare -a ary3=([0]="item4")
英文:
You don't need markers :
#!/usr/bin/env bash
multary(){
while (( $# > 0 )); do
case "$1" in
("-m") declare -n __ary="$2"; __ary=(); shift 2;;
(*) __ary+=("$1"); shift;;
esac
done
}
multary -m ary1 "item1" "item2" -m ary2 "item3" -m ary3 "item4"
declare -p ary1
declare -p ary2
declare -p ary3
# Output :
# declare -a ary1=([0]="item1" [1]="item2")
# declare -a ary2=([0]="item3")
# declare -a ary3=([0]="item4")
答案2
得分: 0
#!/bin/bash
multary(){
source <(
awk '
/^-m/{ f=1; getline arr; print arr"=()"; next }
f{ print arr"+=("$0")" }
' < <(printf "%q\n" "$@")
)
}
multary -m ary1 "item1 itemX" "item2" -m ary2 "item3" -m ary3 "item4"
declare -p ary1
declare -p ary2
declare -p ary3
# Output:
declare -a ary1=([0]="item1 itemX" [1]="item2")
declare -a ary2=([0]="item3")
declare -a ary3=([0]="item4")
英文:
#!/bin/bash
multary(){
source <(
awk '
/^-m/{ f=1; getline arr; print arr"=()"; next }
f{ print arr"+=("$0")" }
' < <(printf "%q\n" "$@")
)
}
multary -m ary1 "item1 itemX" "item2" -m ary2 "item3" -m ary3 "item4"
declare -p ary1
declare -p ary2
declare -p ary3
# Output:
declare -a ary1=([0]="item1 itemX" [1]="item2")
declare -a ary2=([0]="item3")
declare -a ary3=([0]="item4")
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