英文:
Why is `tr` replacing one character with two?
问题
我正在使用 tr（GNU coreutils v8.32）将非基本拉丁字符转换为基本拉丁字符，但它替换了我没有告诉它的字符，或者替换了多于一个期望字符。
示例：
% echo é | tr é e
> ee
发生了什么事？
英文:
I am using tr (GNU coreutils v8.32) to transliterate non-basic-Latin characters into basic Latin, and it is replacing them with characters I didn't tell it to or more than one of the desired character.
Example:
% echo é | tr é e
> ee
What's going on?
答案1
得分: 2
é 有两个字节，可能这就是为什么 tr 生成了两个 e。
您可以通过以下方式实现期望的效果：
echo 'é' | iconv -t ASCII//TRANSLIT
英文:
é has two bytes, maybe that's why tr produces two e.
You can achieve the epxected effect with :
echo 'é' | iconv -t ASCII//TRANSLIT
答案2
得分: 0
I think the issue is that tr is oriented to the transliteration of single bytes, but if you look at your é, you will see it is two bytes, plus a linefeed:
我认为问题在于 tr 只针对单个字节的音译，但如果你看你的 é，你会发现它是两个字节，加上一个换行符：
echo é | xxd
00000000: c3a9 0a ...
I think you need to look to sed which is oriented towards patterns, however long they may be:
我认为你需要使用 sed，它更偏向于处理模式，无论它们有多长：
echo éàéà | sed -e 's/é/elephant/g' -e 's/à/antelope/g'
elephantantelopeelephantantelope
英文:
I think the issue is that tr is oriented to the transliteration of single bytes, but if you look at your é, you will see it is two bytes, plus a linefeed:
echo é | xxd
00000000: c3a9 0a ...
I think you need to look to sed which is oriented towards patterns, however long they may be:
echo éàéà | sed -e 's/é/elephant/g' -e 's/à/antelope/g'
elephantantelopeelephantantelope
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