How can I find matching values in two arrays and print then?

How can I find matching values in two arrays and print then?

I need to make a program in c that the user should enter 10 integers greater than zero and store them in an array. Then the user must enter 10 more integer numerical values greater than zero and store them in another array. The program should display all the values that are part of both arrays, but I can't find a way to do this without making modular code, and I don't want to do this.
Can someone help me?

I tried to use this code but it didn't work

#include <stdio.h>
#include <locale.h>

int main() {	
	setlocale(LC_ALL, "Portuguese");
    int vetor[10], vetor2[10], vetor3[10];
    int i, j , k = 0;

    printf("Digite 10 números inteiros e maiores que zero:\n");

    for (i = 0; i < 10; i++) {
	{   	
        printf("Número %d: ", i + 1);
        scanf("%d", &vetor[i]);

    }while (vetor[i] <=0 );
	}	

	printf("\n\nDigite mais 10 números inteiros e maiores que zero:\n");

    for (i = 0; i < 10; i++) {
	{   	
        printf("Número %d: ", i + 1);
        scanf("%d", &vetor2[i]);

    }while (vetor2[i] <=0 );
	}	
	
    printf("\nValores digitados no vetor 1:\n");
    for (i = 0; i < 10; i++) {
        printf("\n%d ", vetor[i]);
    }

    printf("\n\nValores digitados no vetor 2:\n");
    for (i = 0; i < 10; i++) {
        printf("\n%d ", vetor2[i]);
    }
    
	if (vetor[i] == vetor2[i]) {
    		vetor3[j] = vetor[1];
    		j++;
    for (i = 0; i < j; i++) {
    	printf("\n\nValores que fazem parte nos dois vetores:\n");
        printf("\n%d ", vetor3[j]);
    }
	}

    return 0;
}

@pmacfarlane i make some changes in the code, i don't know if this is what you want, because i didnt understand correctly what you want.

#include <stdio.h>
#include <locale.h>

int main()
{
setlocale(LC_ALL, "Portuguese");
int vetor[10], vetor2[10], vetor3[10];
int i, j = 0;

printf("Enter 10 integers numbers greater than zero:\n");

for (i = 0; i < 10; i++) {
    {
        printf("Number %d: ", i + 1);
        scanf("%d", &vetor[i]);

    }
    while (vetor[i] <= 0);
}

printf("\n\nEnter 10 more integers numbers greater than zero:\n");

for (i = 0; i < 10; i++) {
    {
        printf("Número %d: ", i + 1);
        scanf("%d", &vetor2[i]);

    }
    while (vetor2[i] <= 0)
        ;
}

printf("\nValues entered in vector 1:\n");
for (i = 0; i < 10; i++) {
    printf("\n%d ", vetor[i]);
}

printf("\n\nValues entered in vector 2:\n");
for (i = 0; i < 10; i++) {
    printf("\n%d ", vetor2[i]);
}


if (vetor[i] == vetor2[i]) {
   
    for (i = 0; i < 10; i++) {
        printf("\n\nValues that are present in both arrays:\n");
        printf("\n%d ", vetor[i]);
    }
}

return 0;
}

Here is the result of properly indenting your code. (I used indent -kr on Linux, then added a few newlines):

#include <stdio.h>
#include <locale.h>

int main()
{
    setlocale(LC_ALL, "Portuguese");
    int vetor[10], vetor2[10], vetor3[10];
    int i, j, k = 0;

    printf("Digite 10 números inteiros e maiores que zero:\n");

    for (i = 0; i < 10; i++) {
        {
            printf("Número %d: ", i + 1);
            scanf("%d", &vetor[i]);
        }

        while (vetor[i] <= 0)
            ;
    }

    printf("\n\nDigite mais 10 números inteiros e maiores que zero:\n");

    for (i = 0; i < 10; i++) {
        {
            printf("Número %d: ", i + 1);
            scanf("%d", &vetor2[i]);
        }

        while (vetor2[i] <= 0)
            ;
    }

    printf("\nValores digitados no vetor 1:\n");
    for (i = 0; i < 10; i++) {
        printf("\n%d ", vetor[i]);
    }

    printf("\n\nValores digitados no vetor 2:\n");
    for (i = 0; i < 10; i++) {
        printf("\n%d ", vetor2[i]);
    }

    if (vetor[i] == vetor2[i]) {
        vetor3[j] = vetor[1];
        j++;
        for (i = 0; i < j; i++) {
            printf("\n\nValores que fazem parte nos dois vetores:\n");
            printf("\n%d ", vetor3[j]);
        }
    }

    return 0;
}

You have a weird extra level of {} in the body of your first two for loops. Are those meant to be do ... while() inside there?

Both of your for loops that read in the arrays will, on detecting a number that is <= 0, enter an infinite loop. I suspect that is not what you want.

After your second loop that prints the arrays, you have if (vetor[i] == vetor2[i]). At this point, i is 10, and so you are indexing your arrays out of bounds. This invokes undefined behaviour.

If the undefined behaviour happens to result in the if evaluating true, you then do vetor3[j] = vetor[1];. But j is not initialised at this point. This also invokes undefined behaviour. I'm not sure why you want vetor[1] either.

You then run a loop from 0 to j, printing numbers from vetor3[], even though you only ever possibly set one member of that array.

I'd recommend using an editor that can format your code for you, and running your compiler with more warnings enabled.