英文:
First and Last element of String in brackets when copied to file
问题
Here's the translated content you requested:
<h4>Explanation:</h4>我有一个名为`text()`的函数，它根据一个变量是`0`还是`1`，将一系列字符串附加到列表`Prüftext`中，并将该字符串复制到我的剪贴板。我从两个在函数外部定义的列表中获取要附加的字符串。它们是：```pySetBlock = ["SetBlock1", "SetBlock2", "SetBlock3", "SetBlock4"]
和：
TextBlock = ["TextBlock1", "TextBlock2", "TextBlock3", "TextBlock4"]
我的问题：
当我将字符串复制到文件中时，第一个和最后一个元素都是这样的：
```plaintext
{SetBlock1} TextBlock1 TextBlock2 {SetBlock3}
```
或者当我在函数中切换列表时，我得到这个：
TextBlock1 {SetBlock1} {SetBlock3} TextBlock2
但我想要的是：
SetBlock1 TextBlock1 TextBlock2 SetBlock3
如果我通过Prüftext.append("手动字符串")手动附加一个字符串，它也会出现在大括号中。
因此，这似乎与列表以及它们的访问方式有关？
我已经导入了tkinter作为Tk。
该函数：
def text(pfVar):Prüftext = []dummy = ""if pfVar == 0:Prüftext.append(SetBlock[0])if pfVar == 1:Prüftext.append(SetBlock[1])for i in range(0, len(Indicator)):if Indicator[i] == 1:Prüftext.append(TextBlock[i])if kosten == -1:Prüftext.append(SetBlock[3])if kosten == 1:Prüftext.append(SetBlock[2])if kosten == 0:dummy = dummyr = Tk()r.withdraw()r.clipboard_clear()r.clipboard_append(Prüftext)r.update()r.destroy()print(Prüftext)
我查看了tkinter文档并尝试更改SetBlock和TextBlock中的文本，但没有找到我认为会对我有所帮助的内容。
Please note that certain characters like `ü`, `ö`, and `ß` have been retained in the translation.<details><summary>英文:</summary><h4>Explaination:</h4>I have a function `text()`, which is to append a series of strings to the list `Prüftext`, depending on if a variable is `0` or `1`, and copy that string into my clipboard.I get the strings which are to be appended from two lists, that are defined outside of the function.These are:```pySetBlock = ["SetBlock1","SetBlock2","SetBlock3","SetBlock4"]
and:
TextBlock = ["TextBlock1","TextBlock2","TextBlock3","TextBlock4"]
<hr>
<h4>My Problem:</h4>
When I copy the string into a file, the first and last elements are in curly brackets like this:
{SetBlock1} TextBlock1 TextBlock2 {SetBlock3}
Or when I switch out the lists in the function I get this:
TextBlock1 {SetBlock1} {SetBlock3} TextBlock2
But I want:
SetBlock1 TextBlock1 TextBlock2 SetBlock3
If I append a string after "manually" by doing Prüftext.append("manual string"), it is also in curly brackets.
So it seems to be related in some kind to the lists and how they are accessed?
I have imported tkinter as Tk
<hr>
<h4>The function:</h4>
def text(pfVar):Prüftext = []dummy = ""if pfVar == 0:Prüftext.append(SetBlock[0])if pfVar == 1:Prüftext.append(SetBlock[1])for i in range(0, len(Indicator)):if Indicator[i] == 1:Prüftext.append(TextBlock[i])if kosten == -1:Prüftext.append(SetBlock[3])if kosten == 1:Prüftext.append(SetBlock[2])if kosten == 0:dummy = dummyr = Tk()r.withdraw()r.clipboard_clear()r.clipboard_append(Prüftext)r.update()r.destroy()print(Prüftext)
I have looked at the tkinter documentation and tried to change out the text in the lists SetBlock, and TextBlock but didn't find anything that I think would help me.
答案1
得分: 1
尝试将 r.clipboard_append(Prüftext) 更改为 r.clipboard_append(", ".join(Prüftext))。
英文:
Try to change r.clipboard_append(Prüftext) to r.clipboard_append(", ".join(Prüftext))
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