我有这段糟糕的代码，我试图解析一个包含字典列表的字典列表。
如果 id 匹配特定的 id，我需要输出一个包含 id 和 name 的字典列表，类似于这样：
```python
[{"id": 123}, {'name': 'bob'}]

list1 = [{"id": 123, "job": "nurse", "who":[{"user": "bob_user", "name": "bob"}]}, {"id": 456, "job": "teacher", "who":[{"user": "jim_user", "name": "jim"}]}
list2 = []
keys = ["id", "who"]
for items in list1:
  if items['id'] == 123:
    for key in keys:
      if key == "who":
        for values in items[key]:
          for count in values:
            if count == "name":
              list2.append({key : values[count]})
      else:
        list2.append({key : items[key]})
print(list2)

<details>
<summary>英文:</summary>
I have this awful awful code where I am trying to parse through a list of dictionaries which contain a list of dictionaries.
I need to output a list of dictionaries with the id and name like this if the id matches a certain id. Something like this:

Code currently works but looks like a monkey wrote it! How can I make this more efficient?
</details>
# 答案1
**得分**: 1
How about simply accessing the element of lists and dictionaries together with slicing?
```python
list1 = [
    {"id": 123, "job": "nurse", "who":[{"user": "bob_user", "name": "bob"}]},
    {"id": 234, "job": "programmer", "who":[{"user": "alice_user", "name": "alice"}]},
    {"id": 456, "job": "teacher", "who":[{"user": "jim_user", "name": "jim"}]}
]
# Input
target_keys = ["id", "who"]
target_ids = [123, 234]
# Output
result_list = []
for item in list1:
    if item['id'] in target_ids:
        result_list.append([
            {"id": item[target_keys[0]]},
            {"name": item[target_keys[1]][0]['name']}
        ])
print(result_list)

list1 = [{"id": 123, "job": "nurse", "who": [{"user": "bob_user", "name": "bob"}]},
         {"id": 456, "job": "teacher", "who": [{"user": "jim_user", "name": "jim"}]}]
list2 = []
keys = ["id", "who"]
find_ids = [123, 456]
for data in list1:
    # 在检查“id”是否匹配“find_ids”列表中的id时
    # 将“id”值赋给变量“user_id”
    if (user_id := data.get("id")) in find_ids:
        user_name = data.get("who")[0].get("name")
        list2.append({"id": user_id, "who": user_name})
print(list2)
# 输出:
# [{'id': 123, 'who': 'bob'}, {'id': 456, 'who': 'jim'}]

list1 = [
        {"id": 123, "job": "nurse", "who":[{"user": "bob_user", "name": "bob"}]},
        {"id": 234, "job": "programmer", "who":[{"user": "alice_user", "name": "alice"}]},
        {"id": 456, "job": "teacher", "who":[{"user": "jim_user", "name": "jim"}]}
        ]
# 输入
target_ids = [123, 234]
# 输出
result_list = [{"id": x["id"], "who": x["who"][0]["name"]} for x in list1 if x["id"] in target_ids]
print(result_list)