Is it possible in SQlite3 python that if a row has been previously updated, it cannot be updated for like 5 seconds

huangapple go评论61阅读模式
英文:

Is it possible in SQlite3 python that if a row has been previously updated, it cannot be updated for like 5 seconds

问题

在数据库表中,如果特定行之前已被修改或更新,我希望在一段时间内(比如说我设置的5秒内)不允许修改该行,即使程序尝试修改该行,然后在此之后可以再次修改或更新该行。这是否可能?

英文:

In a database table, if a specific row has been previously modified or updated, I want that row to not be changed or cannot be modified for let's say I set in 5 seconds even if the program is trying to modify that row, then after that the row can be modified or update again. Is that possible?

I didn't try anything yet because I dont have an idea if it is possible or not

答案1

得分: 0

以下是翻译好的部分:

是的,这是可能的。要实现这种行为,您可以向您的表添加一个新列,我们称之为 last_modified。它将获得当前时间戳的默认值。

CREATE TABLE your_table (
    ...
    last_modified TIMESTAMP DEFAULT CURRENT_TIMESTAMP
);

或者

ALTER TABLE your_table ADD COLUMN last_modified TIMESTAMP DEFAULT CURRENT_TIMESTAMP;

现在,每次您想要更新表时,您都可以检查受影响的行是否在最近的5秒内被更新,如果没有,就更新该行;如果是,则抛出错误。

import sqlite3
import time

# 连接到SQLite数据库
conn = sqlite3.connect('your_database.db')
cursor = conn.cursor()

# 如果表不存在,则创建表
cursor.execute('''CREATE TABLE IF NOT EXISTS your_table
                  (id INTEGER PRIMARY KEY AUTOINCREMENT,
                   column1 TEXT,
                   column2 TEXT,
                   last_modified TIMESTAMP DEFAULT CURRENT_TIMESTAMP)''')

# 检查是否可以修改行的函数
def can_modify_row(row_id, interval):
    cursor.execute("SELECT ROUND((JULIANDAY('now') - JULIANDAY(last_modified)) * 86400) FROM your_table WHERE id = ?", (row_id,))
    elapsed_time = cursor.fetchone()[0]
    return elapsed_time > interval

# 更新行,将last_modified时间戳设置为当前时间
def update_row(row_id, column1_value, column2_value):
    cursor.execute("UPDATE your_table SET column1 = ?, column2 = ?, last_modified = CURRENT_TIMESTAMP WHERE id = ?", (column1_value, column2_value, row_id))
    conn.commit()

# 示例用法
row_id = 1
interval = 5  # 秒

if can_modify_row(row_id, interval):
    print("修改行...")
    update_row(row_id, "new_value1", "new_value2")
else:
    print("暂时无法修改行。请稍后再试。")

# 关闭数据库连接
conn.close()

这段代码目前尚未经过测试,但我希望您能理解其思想。

英文:

Yes this is possible. To implement this kind of behaviour you can add a new column to your table let's call it last_modified. Which get's a default value of the current timestamp

CREATE TABLE your_table (
    ...
    last_modified TIMESTAMP DEFAULT CURRENT_TIMESTAMP
);

or

ALTER TABLE your_table ADD COLUMN last_modified TIMESTAMP DEFAULT CURRENT_TIMESTAMP;

Now each time you want to update your table you check if the affected row has been updated in the last 5 seconds if not update the row if yes throw an error.

import sqlite3
import time

# Connect to the SQLite database
conn = sqlite3.connect('your_database.db')
cursor = conn.cursor()

# Create the table if it doesn't exist
cursor.execute('''CREATE TABLE IF NOT EXISTS your_table
                  (id INTEGER PRIMARY KEY AUTOINCREMENT,
                   column1 TEXT,
                   column2 TEXT,
                   last_modified TIMESTAMP DEFAULT CURRENT_TIMESTAMP)''')

# Function to check if a row can be modified
def can_modify_row(row_id, interval):
    cursor.execute("SELECT ROUND((JULIANDAY('now') - JULIANDAY(last_modified)) * 86400) FROM your_table WHERE id = ?", (row_id,))
    elapsed_time = cursor.fetchone()[0]
    return elapsed_time > interval

# Update a row, setting the last_modified timestamp to the current time
def update_row(row_id, column1_value, column2_value):
    cursor.execute("UPDATE your_table SET column1 = ?, column2 = ?, last_modified = CURRENT_TIMESTAMP WHERE id = ?", (column1_value, column2_value, row_id))
    conn.commit()

# Example usage
row_id = 1
interval = 5  # seconds

if can_modify_row(row_id, interval):
    print("Modifying the row...")
    update_row(row_id, "new_value1", "new_value2")
else:
    print("Cannot modify the row yet. Please try again later.")

# Close the database connection
conn.close()

The code is currently untested, but I hope you get the idea

huangapple
  • 本文由 发表于 2023年5月18日 07:24:03
  • 转载请务必保留本文链接:https://go.coder-hub.com/76276794.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定