问题

我想从数组列表中移除一个字符串。例如，一个数组元素可能是 [290..2, 310.1, 310.0]。在这种情况下，要移除的字符串是 290..2。所以基本上我有很多手动输入的数据，我想要排除包含错误输入的整行数据，就像我所示范的例子。是否有现有的函数可以用来解决这个问题？

答案1

得分: 0

根据您的反馈进行了编辑。听起来您可能有一个包含列表的列表？但根据您的代码，我仍然不确定它是一个列表还是数组。这有帮助吗？

list_1 = [[1, 2, "1..1"], [1, 2, 1], [1, 2, 1], [1, 2, "1..1"], [1, 2, "1..1"], [1, 2, 1]]

list_reversed = reversed(list_1)

len_list_1 = len(list_1)

for ind, sublist in enumerate(list_reversed):
    x_t = [isinstance(a, str) for a in sublist]
    if any(x_t):
        print(f"string here!! - {sublist}")
        list_1.pop(len_list_1 - (ind + 1))
    else:
        print(f"No string here - {sublist}")

print(f"\nResult: {list_1}")

结果如下（即删除包含字符串的子列表）：

[[1, 2, 1], [1, 2, 1], [1, 2, 1]]

list_1 = [[1,2,"1..1"], [1,2, 1], [1,2,1], [1,2,"1..1"],[1,2,"1..1"], [1,2, 1]]

list_reversed =  reversed(list_1)

len_list_1 = len(list_1)

for ind, sublist in enumerate(list_reversed):
    x_t = [isinstance(a, str) for a in sublist ] 
    if any(x_t):
        print(f"string here!! - {sublist}")
        list_1.pop(len_list_1-(ind+1))
    else: 
        print(f"No string here - {sublist}")

print(f"\nResult: {list_1}")

[[1, 2, 1], [1, 2, 1], [1, 2, 1]]

答案2

得分: 0

Here's the translated code:

我理解你想从列表中筛选出字符串的部分：
list = ["2...7",1,2,3]
list2 = []
for x in list:
    if not type(x) == str:
        list2.append(x)
    else: ## 不是必需的，但我只是为了确认而添加了这个 ##
        pass
print (list2)

如果你不想创建第二个列表，你也可以使用这种方法：
list = ["2...7",1,2,3]
for x in list:
    if type(x) == str:
        list.remove(x)
print (list)

这是输出[对于两种方法都是]：

[1, 2, 3]

<details>
<summary>英文:</summary>

from what i could understand you want to filter out the string from a list

list = ["2...7",1,2,3]
list2 = []
for x in list:
if not type(x) == str:
list2.append(x)
else: ## not required but i just did it for confirmation ##
pass
print (list2)

And if you don't want to create a second list you can also use this method

list = ["2...7",1,2,3]
for x in list:
if type(x) == str:
list.remove(x)
print (list)

this was the **output** [ for both methods ]

> [1, 2, 3]

</details>



# 答案3
**得分**: 0

这个函数将检查列表并返回仅包含有效浮点数值的列表。

<details>
<summary>英文:</summary>

If you are trying to just keep the float values in the list then this might help: 
    
    def float_values(lst):
        return [val for val in lst if isinstance(val, float)]

This function will check the list and will return a list with only valid float values.


</details>