英文:
Algorithm to rotate a float value between 0 and 360 degrees by +180 degrees
问题
将一个浮点数（将介于0.0和360.0之间）旋转+180度。
因此，0.0将变为180.0
90.0将变为270.0
180.0将变为0.0
270将变为90.0
我正在考虑以下算法，但它似乎有点粗糙？ 有没有更简单的方法：
如果数字小于180，则加上180
否则，如果数字大于180，则减去180。
英文:
I want to take a floating point number (which will be between 0.0 and 360.0) and rotate that value by + 180 degrees.
So 0.0 would become 180.0
90.0 would become 270.0
180.0 would become 0.0
270 would become 90.0
I am thinking of the following algorithm, but it seems a bit crude? Is there a simpler way?:
If number < 180 then add 180
else if number > 180 then subtract 180.
答案1
得分: 2
(number + 180) % 360
模除运算适用于整数，在某些语言中也适用于浮点数（如Python等）。还有像C++中的fmod等特殊函数。
英文:
(number + 180) % 360
Modulo operation for integers, also works for floats in some languages (Python etc). There are also special functions like C++ fmod
答案2
得分: 1
"I think 'just code the your idea as is' is the simplest, and enough. Depending on the language, for example writing like (X<180 ? X+180 : X-180) makes the code look simpler, but the meaning is the same.
I think, thinking some other less straightforward writing styles (e.g. X - 180 * ( (X>=180) - (X<180) ) ) or employing operator that may be unnecessary expensive (e.g. modulo), will be nonsense."
英文:
I think "just code the your idea as is" is the simplest, and enough.
Depending on the language, for example writing like (X<180 ? X+180 : X-180) makes the code look simpler, but the meaning is the same.
I think, thinking some other less straightforward writing styles (e.g. X - 180 * ( (X>=180) - (X<180) ) ) or employing operator that may be unnecessary expensive (e.g. modulo), will be nonsense.
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