英文:
Pyspark Exploding Column on Boolean Conditional
问题
我理解你的问题。你想在Pyspark中对joined_data表按home_code条件进行展开，但只展开在nyc_code表中存在的值。以下是示例代码，用于实现你的目标：
from pyspark.sql.functions import col, explode# 首先，将`joined_data`和`nyc_code`表进行连接，以获取需要的`code`列result_df = joined_data.join(nyc_code, col("cleaned_home_code").contains(col("code")))# 然后，使用explode函数展开`cleaned_home_code`列result_df = result_df.select("poi_code", "cleaned_home_code", "code").withColumn("code", explode("code"))# 现在，`result_df`包含了你期望的结果
这段代码首先连接两个表，然后使用explode函数展开cleaned_home_code列，并确保只展开那些在nyc_code表中存在的值。希望这可以帮助你解决问题。
英文:
I am struggling with exploding on a conditional in Pyspark.
I have two tables:
joined_data:
| poi_code | cleaned_home_code |
|---|---|
| 1 | [{"12": 4, "34":2, "56":8}] |
| 2 | [{"12": 8, "56": 10, "78":4}] |
| 3 | [{"34": 1}] |
and nyc_code:
| code | zipcode |
|---|---|
| 12 | 11221 |
| 56 | 11385 |
| 78 | 10471 |
I would like to explode joined_data on home_code but only for values that exist in nyc_code.
Desired result:
| poi_code | cleaned_home_code | code |
|---|---|---|
| 1 | [{"12": 4, "34":2, "56":8}] | 12 |
| 1 | [{"12": 4, "34":2, "56":8}] | 56 |
| 2 | [{"12": 8, "56": 10, "78":4}] | 12 |
| 2 | [{"12": 8, "56": 10, "78":4}] | 56 |
| 2 | [{"12": 8, "56": 10, "78":4}] | 78 |
Can anyone please advise? I have tried exploding and then filtering out non-nyc codes, the challenge is that my dataset becomes too large to compute in the desired timeframe. This is why I'm wondering if I can apply the filtering condition as I explode, so that I only explode values that meet the desired criteria. I am a spark novice so any help is appreciated.
答案1
得分: 1
Here are the translated parts:
- 导入必要的包：
from pyspark.sql.functions import explode, map_keys
- 展开
cleaned_home_code列并提取键值对：
joined_data = joined_data.withColumn("exp_cleaned_home_code", explode("cleaned_home_code"))joined_data = joined_data.withColumn("home_code_key", map_keys("exp_cleaned_home_code"))joined_data = joined_data.withColumn("home_code_key", explode("home_code_key"))
- 与
nyc_code数据框进行内连接：
joined_nyc = joined_data \.join(nyc_code, joined_data.home_code_key == nyc_code.code) \.orderBy("poi_code") \.drop("home_code_key", "zipcode", "exp_cleaned_home_code")joined_nyc.show(truncate=False)
- 输出结果：
+--------+------------------------------+----+|poi_code|cleaned_home_code |code|+--------+------------------------------+----+|1 |[{56 -> 8, 34 -> 2, 12 -> 4}] |12 ||1 |[{56 -> 8, 34 -> 2, 12 -> 4}] |56 ||2 |[{78 -> 4, 56 -> 10, 12 -> 8}]|12 ||2 |[{78 -> 4, 56 -> 10, 12 -> 8}]|56 ||2 |[{78 -> 4, 56 -> 10, 12 -> 8}]|78 |+--------+------------------------------+----+
Please note that I have translated the code comments, but not the code itself, as per your request.
英文:
Try this:
Importing necessary packages
from pyspark.sql.functions import explode, map_keys
- Explode the
cleaned_home_codecolumns and extract key out of it
joined_data = joined_data.withColumn("exp_cleaned_home_code", explode("cleaned_home_code"))joined_data = joined_data.withColumn("home_code_key", map_keys("exp_cleaned_home_code"))joined_data = joined_data.withColumn("home_code_key", explode("home_code_key"))
- perform an inner join with the
nyc_codeDataFrame
joined_nyc = joined_data \.join(nyc_code, joined_data.home_code_key == nyc_code.code) \.orderBy("poi_code") \.drop("home_code_key", "zipcode", "exp_cleaned_home_code")joined_nyc.show(truncate=False)
Output:
+--------+------------------------------+----+|poi_code|cleaned_home_code |code|+--------+------------------------------+----+|1 |[{56 -> 8, 34 -> 2, 12 -> 4}] |12 ||1 |[{56 -> 8, 34 -> 2, 12 -> 4}] |56 ||2 |[{78 -> 4, 56 -> 10, 12 -> 8}]|12 ||2 |[{78 -> 4, 56 -> 10, 12 -> 8}]|56 ||2 |[{78 -> 4, 56 -> 10, 12 -> 8}]|78 |+--------+------------------------------+----+
答案2
得分: 0
自 Spark 3.1 起，您可以在爆炸之前过滤您的 cleaned_home_code 列，仅保留指定列表中的值。
然而，指定的列表不能是一个数据框，所以您首先需要将您的 nyc_code 转换为 Python 列表。在您的情况下，由于您的 nyc_code 数据框相对较小（约 6000 条记录），您可以收集它并将其传递给 filter 函数以删除不在 nyc_code 中的所有值。然后，您可以爆炸过滤后的列，如下所示：
from pyspark.sql import functions as F# 创建要保留的代码列表kept_codes = [r[0] for r in nyc_code.select(F.col('code').cast('string')).distinct().collect()]# 在过滤后的映射上爆炸result = joined_data.withColumn('code',F.explode(F.filter(F.map_keys(F.col('cleaned_home_code')),lambda c: c.isin(kept_codes))))
然后，您将获得以下 result 数据框：
+--------+----------------------------+----+|poi_code|cleaned_home_code |code|+--------+----------------------------+----+|1 |{56 -> 8, 34 -> 2, 12 -> 4} |56 ||1 |{56 -> 8, 34 -> 2, 12 -> 4} |12 ||2 |{78 -> 4, 56 -> 10, 12 -> 8}|78 ||2 |{78 -> 4, 56 -> 10, 12 -> 8}|56 ||2 |{78 -> 4, 56 -> 10, 12 -> 8}|12 |+--------+----------------------------+----+
英文:
Since Spark 3.1, You can filter your cleaned_home_code column, keeping only values in a specified list before exploding it.
However, this specified list can't be a dataframe so you first need to transform your nyc_code to a python list. In your case, as your nyc_code dataframe is rather small (~6000 records), you can collect it and pass it to the filter function to remove all values not in nyc_code. Then, you can explode filtered column, as follows:
from pyspark.sql import functions as F# create list of codes you want to keepkept_codes = [r[0] for r in nyc_code.select(F.col('code').cast('string')).distinct().collect()]# explode on filtered mapresult = joined_data.withColumn('code',F.explode(F.filter(F.map_keys(F.col('cleaned_home_code')),lambda c: c.isin(kept_codes))))
You then get the following result dataframe:
+--------+----------------------------+----+|poi_code|cleaned_home_code |code|+--------+----------------------------+----+|1 |{56 -> 8, 34 -> 2, 12 -> 4} |56 ||1 |{56 -> 8, 34 -> 2, 12 -> 4} |12 ||2 |{78 -> 4, 56 -> 10, 12 -> 8}|78 ||2 |{78 -> 4, 56 -> 10, 12 -> 8}|56 ||2 |{78 -> 4, 56 -> 10, 12 -> 8}|12 |+--------+----------------------------+----+``</details>
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