制作一个高度和宽度可变的半圆楔形。

huangapple
go评论95阅读模式
英文:

Wedge to make half of a circle with variable height and width

问题

以下是您要翻译的代码部分：

  1. 我试图在绘图中（matplotlib）将半圆放在图中，但最终得到一条线，因为我的y轴最大值是10,000，x轴最大值是5。
  3. 我想知道是否可以将wedge函数的宽度设置为2.5，高度设置为5,000？
  5. def circleplot():
  6.     # 准备图形
  7.     fig, ax = plt.subplots()
  8.     ax.set_xlim(xmin=0, xmax=5)
  9.     ax.set_ylim(ymin=0, ymax=10000)
  11.     w1 = Wedge((2.5, 5000), 2.5, 0, 180, width=0.1, color='black')
  12.     ax.add_patch(w1)
  13.     plt.show()
  15. circleplot()
英文:

I'm trying to put half of a circle in a plot (matplotlib) but instead I end up with a line because my y axis max is 10,000 and my x axis max is 5.

I was wondering if it was possible to set the width to 2.5 and the height to 5,000 for the wedge function?

  1. def circleplot():
  2. 	# preparer le graph
  3. 	fig, ax = plt.subplots()
  4. 	ax.set_xlim(xmin=0, xmax=5)
  5. 	ax.set_ylim(ymin=0, ymax=10000)
  7. 	w1 = Wedge((2.5, 5000), 2.5, 0, 180, width=0.1, color='black')
  8. 	ax.add_patch(w1)
  9. 	plt.show()
  11. circleplot()

答案1

得分: 0

以下是翻译好的代码部分：

  1. import matplotlib.pyplot as plt
  2. import math
  4. def circleplot():
  5.     fig, ax = plt.subplots()
  6.     ax.set_xlim(xmin=0, xmax=5)
  7.     ax.set_ylim(ymin=0, ymax=10000)
  9.     ctr = (2.5, 5000)
  10.     scl = (2.5, 5000)
  11.     xx = []
  12.     yy = []
  13.     for angle in range(180):
  14.         x = ctr[0] + scl[0] * math.cos(angle * math.pi / 180)
  15.         y = ctr[1] + scl[1] * math.sin(angle * math.pi / 180)
  16.         xx.append(x)
  17.         yy.append(y)
  18.     xx.append(xx[0])
  19.     yy.append(yy[0])
  21.     ax.plot(xx, yy)
  23. circleplot()
  24. plt.show()

希望这对您有所帮助。

英文:

Here's what I mean. Just create the points as a circle using normal trigonometry. As long as you apply two different scale for x and y, you can make it look normal. I use 180 points along the half-circle, and it looks pretty smooth. You could probably get by with even fewer than that.

  1. import matplotlib.pyplot as plt
  2. import math
  4. def circleplot():
  5. # preparer le graph
  6.     fig, ax = plt.subplots()
  7.     ax.set_xlim(xmin=0, xmax=5)
  8.     ax.set_ylim(ymin=0, ymax=10000)
  10.     ctr = (2.5, 5000)
  11.     scl = (2.5, 5000)
  12.     xx = []
  13.     yy = []
  14.     for angle in range(180):
  15.         x = ctr[0] + scl[0] * math.cos(angle * math.pi / 180)
  16.         y = ctr[1] + scl[1] * math.sin(angle * math.pi / 180)
  17.         xx.append(x)
  18.         yy.append(y)
  19.     xx.append(xx[0])
  20.     yy.append(yy[0])
  22.     ax.plot(xx,yy)
  24. circleplot()
  25. plt.show()

Output:
制作一个高度和宽度可变的半圆楔形。

huangapple
  • 本文由 发表于 2023年5月15日 01:08:36
  • 转载请务必保留本文链接：https://go.coder-hub.com/76248738.html
  • matplotlib
  • python
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