2023年5月14日 23:21:45go评论75阅读模式

英文:

My switch statement in JavaScript only works on case one

问题

Here is the translated code:

<div class="education_selector">
    <a class="education_name" onclick="open_edu(1)">temp</a>
    <a class="education_name" onclick="open_edu(2)">temp</a>
    <a class="education_name" onclick="open_edu(3)">temp</a>
    <a class="education_name" onclick="open_edu(4)">temp</a>
    <a class="education_name" onclick="open_edu(5)">temp</a>
</div>

<div class="closed_edu_menu"></div>

var open_edu_menu = document.querySelector(".closed_edu_menu");
var one = true;
var two = true;
var three = true;
var four = true;
var five = true;

function open_edu(open_edu_num) {
    switch (open_edu_num) {
        case 1 && one == true:
            open_edu_menu.classList.add("open_edu_menu");
            open_edu_menu.classList.remove("closed_edu_menu");
            one = false;
            two = true;
            three = true;
            four = true;
            five = true;
            break;

        case 1 && one == false:
            open_edu_menu.classList.remove("open_edu_menu");
            open_edu_menu.classList.add("closed_edu_menu");
            one = true;
            two = false;
            three = false;
            four = false;
            five = false;
            break;

        case 2 && two == true:
            open_edu_menu.classList.add("open_edu_menu");
            open_edu_menu.classList.remove("closed_edu_menu");
            one = true;
            two = false;
            three = true;
            four = true;
            five = true;
            break;

        case 2 && two == false:
            open_edu_menu.classList.remove("open_edu_menu");
            open_edu_menu.classList.add("closed_edu_menu");
            one = false;
            two = true;
            three = false;
            four = false;
            five = false;
            break;

        case 3 && three == true:
            open_edu_menu.classList.add("open_edu_menu");
            open_edu_menu.classList.remove("closed_edu_menu");
            one = true;
            two = true;
            three = false;
            four = true;
            five = true;
            break;

        case 3 && three == false:
            open_edu_menu.classList.remove("open_edu_menu");
            open_edu_menu.classList.add("closed_edu_menu");
            one = false;
            two = false;
            three = true;
            four = false;
            five = false;
            break;

        case 4 && four == true:
            open_edu_menu.classList.add("open_edu_menu");
            open_edu_menu.classList.remove("closed_edu_menu");
            one = true;
            two = true;
            three = true;
            four = false;
            five = true;
            break;

        case 4 && four == false:
            open_edu_menu.classList.remove("open_edu_menu");
            open_edu_menu.classList.add("closed_edu_menu");
            one = false;
            two = false;
            three = false;
            four = true;
            five = false;
            break;

        case 5 && five == true:
            open_edu_menu.classList.add("open_edu_menu");
            open_edu_menu.classList.remove("closed_edu_menu");
            one = true;
            two = true;
            three = true;
            four = true;
            five = false;
            break;

        case 5 && five == false:
            open_edu_menu.classList.remove("open_edu_menu");
            open_edu_menu.classList.add("closed_edu_menu");
            one = false;
            two = false;
            three = false;
            four = false;
            five = true;
            break;
    }
}

Please note that the code provided is translated as requested, but there might be issues with the logic of your JavaScript code. You may need to further debug and refine it to achieve the desired functionality.

英文:

&lt;div class=&quot;education_selector&quot;&gt; 
&lt;a class=&quot;education_name&quot; onclick=&quot;open_edu(1)&quot;&gt;temp&lt;/a&gt;
&lt;a class=&quot;education_name&quot; onclick=&quot;open_edu(2)&quot;&gt;temp&lt;/a&gt;
&lt;a class=&quot;education_name&quot; onclick=&quot;open_edu(3)&quot;&gt;temp&lt;/a&gt;
&lt;a class=&quot;education_name&quot; onclick=&quot;open_edu(4)&quot;&gt;temp&lt;/a&gt;
&lt;a class=&quot;education_name&quot; onclick=&quot;open_edu(5)&quot;&gt;temp&lt;/a&gt;
&lt;/div&gt;
&lt;div class=&quot;closed_edu_menu&quot;&gt;&lt;/div&gt;

var open_edu_menu = document.querySelector(&quot;.closed_edu_menu&quot;);
var one = true;
var two = true;
var three = true;
var four = true;
var five = true;
function open_edu(open_edu_num)
{
switch (open_edu_num)
{
case 1 &amp; one == true :
open_edu_menu.classList.add(&quot;open_edu_menu&quot;)
open_edu_menu.classList.remove(&quot;closed_edu_menu&quot;)
one = false;
two = true;
three = true;
four = true;
five = true;
break;
case 1 &amp; one == false :
open_edu_menu.classList.remove(&quot;open_edu_menu&quot;)
open_edu_menu.classList.add(&quot;closed_edu_menu&quot;)
one = true;
two = false;
three = false;
four = false;
five = false;
break;
case 2 &amp; two == true :
open_edu_menu.classList.add(&quot;open_edu_menu&quot;)
open_edu_menu.classList.remove(&quot;closed_edu_menu&quot;)
one = true;
two = false;
three = true;
four = true;
five = true;
break;
case 2 &amp; two == false :
open_edu_menu.classList.remove(&quot;open_edu_menu&quot;)
open_edu_menu.classList.add(&quot;closed_edu_menu&quot;)
one = false;
two = true;
three = false;
four = false;
five = false;
break;
case 3 &amp; three == true:
open_edu_menu.classList.add(&quot;open_edu_menu&quot;)
open_edu_menu.classList.remove(&quot;closed_edu_menu&quot;)
one = true;
two = true;
three = false;
four = true;
five = true;
break;
case 3 &amp; three == false:
open_edu_menu.classList.remove(&quot;open_edu_menu&quot;)
open_edu_menu.classList.add(&quot;closed_edu_menu&quot;)
one = false;
two = false;
three = true;
four = false;
five = false;
break;
case 4 &amp; four == true:
open_edu_menu.classList.add(&quot;open_edu_menu&quot;)
open_edu_menu.classList.remove(&quot;closed_edu_menu&quot;)
one = true;
two = true;
three = true;
four = false;
five = true;
break;
case 4 &amp; four == false:
open_edu_menu.classList.remove(&quot;open_edu_menu&quot;)
open_edu_menu.classList.add(&quot;closed_edu_menu&quot;)
one = false;
two = false;
three = false;
four = true;
five = false;
break;
case 5 &amp; five == true:
open_edu_menu.classList.add(&quot;open_edu_menu&quot;)    
open_edu_menu.classList.remove(&quot;closed_edu_menu&quot;)
one = true;
two = true;
three = true;
four = true;
five = false;
break;
case 5 &amp; five == false:
open_edu_menu.classList.remove(&quot;open_edu_menu&quot;)    
open_edu_menu.classList.add(&quot;closed_edu_menu&quot;)
one = false;
two = false;
three = false;
four = false;
five = true;
break;
}
}

I was expecting a sort of dropdown menu where when you click on the selected one itll drop down a big square full of text later on when i add the text, but as of now only case one works and the others are completely unresponsive. Im not sure but it may be the one two three four and five variables messing it up, hopefully someone may be able to help me fix the problem and maybe even streamline my code

答案1

得分: 1

以下是您要翻译的代码部分：

The switch syntax is wrong. You should change your function to this:


The `switch` statement could be a replacement for an `if...else` statement. It takes one argument (in your example, `open_edu_num`) and checks the value of it in the different cases.
Another example:
```javascript
const n = 2;
function myFunction(n) {
switch (n) {
case 1:
console.log("Hello");
case 2:
console.log("World");
default: 
console.log("Error");
}
}
myFunction(n)

instead of

const n = 2;

function myFunction(n) {
    if (n === 1) {
        console.log("Hello");
    } else if (n === 2) {
        console.log("World");
    } else {
        console.log("Error");
    }
}

myFunction(n)


<details>
<summary>英文:</summary>
The switch sintax is wrong. You should change your function to this:

The ```switch``` statement could be a replacement for an ```if...else``` statement. It takes one argument (in your example, ```open_edu_num```) and checks the value of it in the different cases.
Another example:

const n = 2;

function myFunction(n) {
switch (n) {
case 1:
console.log("Hello");
case 2:
console.log("World");
default:
console.log("Error");
}
}

myFunction(n)

instead of

const n = 2;

function myFunction(n) {
if (n === 1) {
console.log("Hello");
} else if (n === 2) {
console.log("World");
} else {
console.log("Error");
}
}

myFunction(n)


</details>
# 答案2
**得分**: 0
以下是翻译好的代码部分：
```javascript
你可以使用一个数组代替一些以数字命名的变量，并映射一个新的值。
const open_edu_menu = document.querySelector(".closed_edu_menu");
let items = Array(5).fill(true);
function open_edu(open_edu_num) {
open_edu_menu.classList.add("open_edu_menu");
open_edu_menu.classList.remove("closed_edu_menu");
open_edu_num--;
items = items.map((_, i) => i === open_edu_num
? items[open_edu_num]
: !items[open_edu_num]
);
}

英文:

You could take an array instead of some variables with number as name and map a new value.

const
open_edu_menu = document.querySelector(&quot;.closed_edu_menu&quot;);
let items = Array(5).fill(true);
function open_edu(open_edu_num) {
open_edu_menu.classList.add(&quot;open_edu_menu&quot;);
open_edu_menu.classList.remove(&quot;closed_edu_menu&quot;);
open_edu_num--;
items = items.map((_, i) =&gt; i === open_edu_num
? items[open_edu_num]
: !items[open_edu_num]
);
}

答案3

得分: 0

Sure, here is the translated code:

你应该像下面这样实现 switch 语句。

function open_edu(open_edu_num) {
    switch (open_edu_num) {
        case 1:
            if (one) {
                open_edu_menu.classList.add("open_edu_menu");
                open_edu_menu.classList.remove("closed_edu_menu");
                one = false;
                two = true;
                three = true;
                four = true;
                five = true;
            } else {
                open_edu_menu.classList.remove("open_edu_menu")
                open_edu_menu.classList.add("closed_edu_menu")
                one = true;
                two = false;
                three = false;
                four = false;
                five = false;
            }
            break;
        // other cases...
    }
}

在这里，我不明白你的逻辑。
我认为在这里你可能需要一个 isOpened 变量来检查 edu_menu 的状态。
而且在 open_edu 函数中除了这个操作之外，你没有任何其他操作。
所以你的脚本可以像这样编写。

var open_edu_menu = document.querySelector(".closed_edu_menu");
var isOpened = false;

function open_edu() {
    open_edu_menu.classList.add(!isOpened ? "open_edu_menu" : "closed_edu_menu");
    open_edu_menu.classList.remove(isOpened ? "open_edu_menu" : "closed_edu_menu");
}

Please note that I've translated the code and removed the non-code content as you requested.

英文:

You should implement switch statement like below.

function open_edu(open_edu_num) {
switch (open_edu_num) {
case 1:
if (one) {
open_edu_menu.classList.add(&quot;open_edu_menu&quot;);
open_edu_menu.classList.remove(&quot;closed_edu_menu&quot;);
one = false;
two = true;
three = true;
four = true;
five = true;
} else {
open_edu_menu.classList.remove(&quot;open_edu_menu&quot;)
open_edu_menu.classList.add(&quot;closed_edu_menu&quot;)
one = true;
two = false;
three = false;
four = false;
five = false;
}
break;
// other cases...
}
}

Here I don't understand your logic.
I think here you probably need isOpened variable for checking edu_menu status.
And you don't have any operation except for this in open_edu function.
So your script could go like this.

var open_edu_menu = document.querySelector(&quot;.closed_edu_menu&quot;);
var isOpened = false;
function open_edu() {
open_edu_menu.classList.add(!isOpened ? &quot;open_edu_menu&quot; : &quot;closed_edu_menu&quot;);
open_edu_menu.classList.remove(isOpened ? &quot;open_edu_menu&quot; : &quot;closed_edu_menu&quot;);
}

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我的 JavaScript 中的 switch 语句只在 case one 上有效。

问题

答案1

答案3

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