英文:
Possible to return a function that takes variable number of parameters
问题
你好，以下是您要翻译的内容：
在C#中是否可能返回一个函数，该函数接受可变数量的参数并与"params"关键字相同的方式工作（即具有此签名 `string Combine(params string[] theRest)`）？
这是我的尝试：
private Func<string[], string> CreateCombineFunction(string baseUrl, char delim)
{
return theRest =>
baseUrl.TrimEnd(delim) + delim +
string.Join(delim.ToString(), theRest.Select(r => r!.Trim(delim).ToArray()));
}
使用：
var combineFunction = CreateCombineFunction("http://blabla/", '/');
var combinedStr = combineFunction(new[] { "this", "works" });
// var combinedStr = combineFunction("this", "does", "not", "work");
英文:
Is it possible in C# to return a function that takes a variable number of arguments and works in the same way as params works (i.e., as this signature string Combine(params string[] theRest))?
Here is my attempt:
private Func<string[], string> CreateCombineFunction(string baseUrl, char delim)
{
return theRest =>
baseUrl.TrimEnd(delim) + delim +
string.Join(delim.ToString(), theRest.Select(r => r!.Trim(delim).ToArray());
}
Usage:
var combineFunction = CreateCombineFunction("http://blabla/", '/');
var combinedStr = combineFunction(new[] { "this", "works" });
// var combinedStr = combineFunction("this", "does", "not", "work");
答案1
得分: 2
Create a delegate that takes a params argument:
创建一个接受 params 参数的委托：
delegate string Foo(params string[] strings);
Use the delegate as a return type:
将委托用作返回类型：
private Foo CreateCombineFunction(string baseUrl, char delim)
{
return theRest =>
baseUrl.TrimEnd(delim) + delim +
string.Join(delim.ToString(), theRest.Select(r => r.Trim(delim)));
}
Invoke the returned delegate:
调用返回的委托：
var combineFunction = CreateCombineFunction("http://blabla/", '/');
var combinedStr = combineFunction("this", "does", "actually", "work");
英文:
Create a delegate that takes a params argument:
delegate string Foo(params string[] strings);
Use the delegate as return type:
private Foo CreateCombineFunction(string baseUrl, char delim)
{
return theRest =>
baseUrl.TrimEnd(delim) + delim +
string.Join(delim.ToString(), theRest.Select(r => r.Trim(delim)));
}
Invoke the returned delegate:
var combineFunction = CreateCombineFunction("http://blabla/", '/');
var combinedStr = combineFunction("this", "does", "actually", "work");
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