英文:
Why is empty data being transmitted when sending an ajax request to jquery post?
问题
<!DOCTYPE html>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<head>
</head>
<body>
<div id="all-comments"></div>
<input type="hidden" name="page_id" value="1">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script>
$(document).ready(function() {
let page_id = $('input[name="page_id"]').val();
$.ajax({
url: 'vender/show_comment.php',
type: 'POST',
data: {
page_id: page_id
}
});
setTimeout(function() {
$("#all-comments").load("vender/show_comment.php")
}, 1000);
});
</script>
</body>
show_comment.php
<?php
$page_id=$_POST['page_id'];
if(empty($page_id))
$str="I'm empty";
else
$str=$page_id;
?>
<div class="new-comment">
<p><?php echo $str?></p>
<p><?php echo $str?></p>
</div>
I take data from input and pass it through ajax, as a result, I get "I'm empty". Why doesn't it output the input value?
Although when I receive the same data by pressing the button and send them to the server, they will not be empty. But I need to do a data offset when the page loads
英文:
<!DOCTYPE html>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<head>
</head>
<body>
<div id="all-comments"></div>
<input type="hidden" name="page_id" value="1">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script>
$(document).ready(function() {
let page_id = $('input[name="page_id"]').val();
$.ajax({
url: 'vender/show_comment.php',
type: 'POST',
data: {
page_id: page_id
}
});
setTimeout(function() {
$("#all-comments").load("vender/show_comment.php")
}, 1000);
});
</script>
</body>
show_comment.php
<?php
$page_id=$_POST['page_id'];
if(empty($page_id))
$str="I'm empty";
else
$str=$page_id;
?>
<div class="new-comment">
<p><?php echo $str?></p>
<p><?php echo $str?></p>
</div>
I take data from input and pass it through ajax, as a result, I get "I'm empty". Why doesn't it output the input value?
Although when I receive the same data by pressing the button and send them to the server, they will not be empty. But I need to do a data offset when the page loads
答案1
得分: 1
第一个请求是一个POST请求，带有一个载荷，但你忽略了响应。
第二个请求是一个GET请求，没有载荷，并将响应放入了名为"all-comments"的元素中。
你没有做任何事情来在两个请求之间保持数据。
你可以完全删除$.ajax调用，将你的load调用改成POST请求并在其中包含数据：
$("#all-comments").load("vender/show_comment.php", { page_id })
数据仍然不会在后续的GET请求中持久保存，这通常是评论系统的一个可取特性。
要做到这一点，你需要将数据存储在某个地方（通常选择数据库），然后在后续的请求中检索它。
粗略的伪代码大致如下：
如果是POST请求
如果数据无效
以错误方式响应
否则
将数据插入数据库
从数据库中获取数据
生成HTML
以HTML形式响应
英文:
You are making two different requests.
The first request is a POST request, with a payload, but you ignore the response.
$.ajax({
url: 'vender/show_comment.php',
type: 'POST',
data: {
page_id: page_id
}
});
The second request is a GET request, without a payload, and you drop the response into the all-comments element.
$("#all-comments").load("vender/show_comment.php")
You haven't done anything to persist the data between two requests.
You could remove the $.ajax call entirely and make your load call a POST request and include the data there:
$("#all-comments").load("vender/show_comment.php", { page_id })
The data still won't be persisted for subsequent GET requests which is generally a desirable feature of comment systems.
To do that you'll need to store the data somewhere (a database is the usual choice) and then retrieve it in subsequent requests.
Rough pseudo-code would look something along the lines of:
if IS POST REQUEST
if DATA IS NOT VALID
respond with error
else
insert data into database
get data from database
generate html
respond with html
答案2
得分: -1
你必须等待回应：
$.ajax({
url: 'vender/show_comment.php',
type: 'POST',
data: { 'page_id' : page_id },
success: function(response) {
$("#all-comments").html(response);
}
});
英文:
You have to wait for the response:
$.ajax({
url: 'vender/show_comment.php',
type: 'POST',
data: { 'page_id' : page_id },
success: function(response) {
$("#all-comments").html(response);
}
});
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论