头部和尾部如何在C++中连接?

huangapple go评论118阅读模式
英文:

How head and tail is connected in c++?

问题

以下是代码的翻译部分:

  1. #include <iostream>
  2. using namespace std;
  3. class Node
  4. {
  5. public:
  6. int data;
  7. Node *next;
  8. };
  9. int main()
  10. {
  11. Node *head = NULL; // 将头指针初始化为空
  12. Node *tail = NULL; // 将尾指针初始化为空
  13. // 创建循环以向链表添加新节点
  14. for (int i = 1; i <= 5; i++)
  15. {
  16. Node *newNode = new Node(); // 创建一个新的节点对象
  17. newNode->data = i; // 为新节点设置数据变量
  18. newNode->next = NULL; // 将下一个指针设置为空
  19. // 如果列表为空,则将头和尾指针设置为新节点
  20. if (head == NULL)
  21. {
  22. head = newNode;
  23. tail = newNode;
  24. }
  25. // 否则,将新节点添加到列表的末尾,并更新尾指针
  26. else
  27. {
  28. tail->next = newNode;
  29. tail = newNode;
  30. }
  31. }
  32. // 打印出链表
  33. Node *current = head;
  34. while (current != NULL)
  35. {
  36. cout << current->data << " ";
  37. current = current->next;
  38. }
  39. return 0;
  40. }

希望这能帮助你理解代码中如何连接头指针和尾指针以及如何将尾指针的地址传递给头指针。

英文:

I got this code from chat GPT.Can anyone explain me..How head and tail is connected in above code,because i am unable to understand that how address of tail is passed to head.

here is my code:

  1. #include &lt;iostream&gt;
  2. using namespace std;
  3. class Node
  4. {
  5. public:
  6. int data;
  7. Node *next;
  8. };
  9. int main()
  10. {
  11. Node *head = NULL; // Initialize the head pointer to null
  12. Node *tail = NULL; // Initialize the tail pointer to null
  13. // Create a loop to add new nodes to the linked list
  14. for (int i = 1; i &lt;= 5; i++)
  15. {
  16. Node *newNode = new Node(); // Create a new node object
  17. newNode-&gt;data = i; // Set the data variable for the new node
  18. newNode-&gt;next = NULL; // Set the next pointer to null
  19. // If the list is empty, set the head and tail pointers to the new node
  20. if (head == NULL)
  21. {
  22. head = newNode;
  23. tail = newNode;
  24. }
  25. // Otherwise, add the new node to the end of the list and update the tail pointer
  26. else
  27. {
  28. tail-&gt;next = newNode;
  29. tail = newNode;
  30. }
  31. }
  32. // Print out the linked list
  33. Node *current = head;
  34. while (current != NULL)
  35. {
  36. cout &lt;&lt; current-&gt;data &lt;&lt; &quot; &quot;;
  37. current = current-&gt;next;
  38. }
  39. return 0;
  40. }

答案1

得分: 1

headtail 通过内部元素相连接。

在开始时,它们都是 NULL,尽管最好使用 nullptr

当第一个节点被添加时,它们都指向它。之后,tail 将始终指向最后一个元素,head 指向第一个元素。

操作 状态
开始 head = tail = NULL
第一次插入 head = tail = 新节点 -> NULL
第二次插入 head = 第一个节点 -> tail = 第二个节点 -> NULL
第三次插入 head = 第一个节点 -> 第二个节点 -> tail = 第三个节点 -> NULL

这里,-> 表示节点的 next 字段指向的位置。等号表示了在每个状态下 headtail 的值。

英文:

head and tail are connected through the inner elements.

At the start, they are both NULL, although it is better to use nullptr.

When the first node is added, both point to it. After that. tail will always point to the last element and head to the first.

action state after
start head = tail = NULL
first insert head = tail = new node -> NULL
second insert head = first node -> tail = second node -> NULL
third insert head = first node -> second node -> tail = third node -> NULL

Here, the convencion -&gt; means to where the next field of the node point to. The equals sign, is to say what is the value of head and tail in each state.

huangapple
  • 本文由 发表于 2023年5月14日 00:09:33
  • 转载请务必保留本文链接:https://go.coder-hub.com/76243707.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定