How to get value from tuple except known one?

Suppose we have a tuple with two elements:

a = (1, N)

or

a = (N, 1)

I know that one of the elements is 1, the position is unknown and I need to get value of second element other than 1.

Is there a way in Python to get it without iterating the tuple?

The built-in values of True and False, when used in the context of an integer, equate to 1 and 0 respectively. Therefore with no explicit if/else:

N = 99
a = 1, N
b = N, 1
print(a[a[0]==1])
print(b[b[0]==1])

Output:

99
99

Try use an if/else statement

if a[0] == 1:
   N = a[1]
else:
   N = a[0]

Or, to shorten this to one line, you could use the ternary operator:

N = a[0] if a[1] == 1 else a[1]

You can go with if/else

a = (1, N)  #or a = (N, 1)
print(a[0] if a[0]!=1 else a[1])
#output
N