Trying to call a function in an "if... else..." statement, and its saying that the function below isn't defined

y = 0
x = 10
print("TRUE" if y>x else theloop())
def theloop():
 while y < 11:
    print(f"Number is {y}!")
    y = y + 1

I want y to keep on getting bigger by 1 until it becomes bigger than x and print "TRUE", but each time it keeps saying the function isn't defined.

I tried this right here and it seems to work for some reason. But whenever I want y to increase by 1, it completely stops working.

y=0
x=10
def theloop():
    while y < x:
       print(y+1)
print("true" if y>x else theloop())

First thing:

In the global scope, you want to define a function before you call it.
This explains why your first code doesn't work. Python hasn't defined the function yet and you're calling it before it has a chance to access it.

print("TRUE" if y>x else theloop())
# Python hasn't seen this when you call the function
def theloop():
    while y < x:
       print(y+1)

Second thing:

The code you wrote that runs only prints (y+1)... it does not actually increase y by 1.

Also, y is not accessible within the function so:

Define it locally before the while loop like this:

x = 10
def the_loop():
    # define y locally
    y = 0
    while y < x:
        # increases y by 1
        y += 1
        print(y)
print("true" if y > x else the_loop())

Pass it in as an argument if y might change:

x = 10
y = 0
# pass y in as an argument 
def the_loop(y):
    while y < x:
        # increases y by 1
        y += 1
        print(y)
print("true" if y > x else the_loop(y))

Use the global keyword (see this post)

y = 0
x = 10
def theloop():
    global y
    while y < x:
       y += 1
       print(y)
print("true" if y > x else the_loop())

Using global keyword actually changes the original variable and now y = 10 is accessible outside of the function.
More on globals here