SDT到ts文件的CRC-32生成

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英文:

Formation of CRC-32 for SDT to ts. file

问题

我的任务是从服务器捕获视频流并将其写入ts文件。当我尝试将SDT包写入ts文件时,遇到了一个问题。我通过字节手动形成数据包,但是我无法计算SDT末尾的4个字节的CRC-32校验和。(使用golang)

我尝试根据已写入SDT包的数据的校验和来获取CRC,但是它不起作用。在逐字节解析的SDT中,CRC与我计算的不同。

英文:

My task is to capture the videostream from the server and write it to ts. files. I ran into a problem when trying to write a SDT package to ts. I form the packet manually by bytes and I can’t figure out how to calculate 4 bytes of CRC-32 for the end of SDT. (used golang)

I tried to get the CRC based on the checksum of the data already written to the SDT packet, but it doesn't work. In the byte-by-byte parsed SDT, CRC was different from what I calculated.

答案1

得分: 2

如果你在谈论MPEG-2,那么CRC的定义如下:

width=32 poly=0x04c11db7 init=0xffffffff refin=false refout=false xorout=0x00000000 check=0x0376e6e7 residue=0x00000000 name="CRC-32/MPEG-2"

RFC 4326中有一个例子:

00 3f 86 dd 00 01 02 03 04 05 60 00 00 00 00 0d
3a 40 20 01 0d b8 30 08 19 65 00 00 00 00 00 00
00 01 20 01 0d b8 25 09 19 62 00 00 00 00 00 00
00 02 80 00 9d 8c 06 38 00 04 00 00 00 00 00 7c
17 17 63

其中最后四个字节是它之前所有字节的CRC-32/MPEG-2(按大端顺序)。

以下是计算该CRC的示例C代码:

#include <stddef.h>
#include <stdint.h>

uint32_t crc32mpeg2(uint32_t crc, void const *mem, size_t len) {
    unsigned char const *data = mem;
    if (data == NULL)
        return 0xffffffff;
    for (size_t i = 0; i < len; i++) {
        crc ^= (uint32_t)data[i] << 24;
        for (unsigned k = 0; k < 8; k++) {
            crc = crc & 0x80000000 ? (crc << 1) ^ 0x4c11db7 : crc << 1;
        }
    }
    return crc;
}

(当mem等于NULL时,返回初始CRC值。)

英文:

If you're talking about MPEG-2, then the CRC definition is:

width=32 poly=0x04c11db7 init=0xffffffff refin=false refout=false xorout=0x00000000 check=0x0376e6e7 residue=0x00000000 name=&quot;CRC-32/MPEG-2&quot;

There is an example in RFC 4326:

00 3f 86 dd 00 01 02 03 04 05 60 00 00 00 00 0d
3a 40 20 01 0d b8 30 08 19 65 00 00 00 00 00 00
00 01 20 01 0d b8 25 09 19 62 00 00 00 00 00 00
00 02 80 00 9d 8c 06 38 00 04 00 00 00 00 00 7c
17 17 63

where the last four bytes of that is the CRC-32/MPEG-2 (in big-endian order) of all of the bytes that precede it.

Here is example C code to calculate that CRC:

#include &lt;stddef.h&gt;
#include &lt;stdint.h&gt;

uint32_t crc32mpeg2(uint32_t crc, void const *mem, size_t len) {
    unsigned char const *data = mem;
    if (data == NULL)
        return 0xffffffff;
    for (size_t i = 0; i &lt; len; i++) {
        crc ^= (uint32_t)data[i] &lt;&lt; 24;
        for (unsigned k = 0; k &lt; 8; k++) {
            crc = crc &amp; 0x80000000 ? (crc &lt;&lt; 1) ^ 0x4c11db7 : crc &lt;&lt; 1;
        }
    }
    return crc;
}

(When called with mem equal to NULL, the initial CRC value is returned.)

答案2

得分: 2

以下是Mark Adler提供的相同(Golang)代码(如果有人需要):

func CalcCRC32(data []byte) uint32 {

	var crc uint32 = 0xffffffff

	if data == nil {
		return crc
	}

	for _, v := range data {
		crc ^= uint32(v) << 24

		for j := 0; j < 8; j++ {
			if (crc & 0x80000000) != 0 {
				crc = (crc << 1) ^ 0x04C11DB7
			} else {
				crc <<= 1
			}
		}
	}

	return crc
}
英文:

Here is the same (Golang) code as provided by Mark Adler (in case anyone needs it):

func CalcCRC32(data []byte) uint32 {

	var crc uint32 = 0xffffffff

	if data == nil {
		return crc
	}

	for _, v := range data {
		crc ^= uint32(v) &lt;&lt; 24

		for j := 0; j &lt; 8; j++ {
			if (crc &amp; 0x80000000) != 0 {
				crc = (crc &lt;&lt; 1) ^ 0x04C11DB7
			} else {
				crc &lt;&lt;= 1
			}
		}
	}

	return crc
}

huangapple
  • 本文由 发表于 2023年5月12日 14:47:07
  • 转载请务必保留本文链接:https://go.coder-hub.com/76233763.html
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