英文:
pyparsing: NotAny(FollowedBy()) failing
问题
import pyparsing as ppfrom pyparsing import *def pyparsing_test():data = "[gog1] [G1] [gog2] [gog3] [gog4] [G2] [gog5] [G3] [gog6]"poi_type = Word(alphas).set_results_name('type')poi = Suppress('[') + poi_type + Word(nums) + Suppress(']')def cnd_is_type(val):return lambda toks: toks.type == valdef cnd_is_not_type(val):return lambda toks: toks.type != valpoi_gog = poi('gog').add_condition(cnd_is_type('gog'))poi_g = poi('g').add_condition(cnd_is_type('G'))poi_not_g = poi('not_g').add_condition(cnd_is_not_type('G'))pattern = poi_gog + ~poi_gr = pattern.search_string(data)print(data)print('=' * 10)print(r)
英文:
i have some input data like
[gog1] [G1] [gog2] [gog3] [gog4] [G2] [gog5] [G3] [gog6]
and want to find all gogs, if not G after it. so in this case i want to get gog2 and gog3 (and maybe gog6).
looks pretty simple, rigth? but i failed 
import pyparsing as ppfrom pyparsing import *def pyparsing_test():# this also dont helps# ParserElement.enable_left_recursion(force=True)data=""" [gog1] [G1] [gog2] [gog3] [gog4] [G2] [gog5] [G3] [gog6] """poi_type = Word(alphas).set_results_name('type')poi = Suppress('[') + poi_type + Char(nums) + Suppress(']')def cnd_is_type(val):return lambda toks: toks.type==valdef cnd_is_not_type(val):return lambda toks: toks.type!=valpoi_gog=poi('gog').add_condition(cnd_is_type('gog'))poi_g=poi('g').add_condition(cnd_is_type('G'))poi_not_g=poi('not_g').add_condition(cnd_is_not_type('G'))pattern = poi_gog + ~poi_g#WTF this finds only `gog6`, why??pattern = poi_gog + NotAny(FollowedBy(poi_g))#WTF same, only `gog6`pattern = poi_gog + poi_not_g.suppress()#WTF this works better but find only `gog2`, why not `gog3` also?r=pattern.search_string(data)print(data)print('='*10)print(r)
答案1
得分: 0
我会选择使用正则表达式模块 re
import redata = """[gog1] [G1] [gog2] [gog3] [gog4] [G2] [gog5] [G3] [gog6] """m = re.findall(r'\[(gog.)(?!...G)', data)print(m)
结果是：
['gog2', 'gog3', 'gog6']
如果需要，正则表达式仍然可以进一步改进，以排除最后的 gog？和/或处理大于9的数字，或者使其更健壮。
英文:
I would go for the regexp module re
import redata=""" [gog1] [G1] [gog2] [gog3] [gog4] [G2] [gog5] [G3] [gog6] """m = re.findall('\[(gog.)(?!...G)', data)print(m)
the result is:
['gog2', 'gog3', 'gog6']
The regexp can still be improved if you want to exclute the last gog ? and/or you need to handle numbers larger than 9 if needed ? or make it more robust.
答案2
得分: 0
Finally, we know what's happening, thanks to @ptmcg!
His original answer on GitHub here.
Summary:
First of all, you need to use grouping with StringEnd(), and this one works:
pattern = poi_gog + FollowedBy(Group(poi_not_g) | StringEnd())
Regarding the title problem - NotAny() has a bug; it skips parse actions and conditions. The current version of pyparsing is 3.0.9.
英文:
Finnaly, we know whats happens, thanks to @ptmcg!
His original answer on github https://github.com/pyparsing/pyparsing/issues/482#issuecomment-1546779260.
Summary:
First of all, need to use grouping with StringEnd() and this one works:
pattern = poi_gog + FollowedBy(Group(poi_not_g) | StringEnd())
About title problem - NotAny() have bug, it skips parse actions (and conditions). Current version pyparsing 3.0.9
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