英文:
Typescript: define types for list of keys
问题
我有一个频道列表，类似于：
type Channels = 'Channel1' | 'Channel2' | ....
每个频道都有自己的类型，所以我正在使用这段代码：
type BaseTypes = {[key in Channels]: object};
interface ChannelTypes extends BaseTypes {
Channel1: {/* 定义所需数据 */},
Channel2: {/* 定义所需数据 */},
}
我想找到一种方法，当我向频道添加一个值时，强制我更新 ChannelTypes，并拒绝在 Channels 中未定义的任何键在 ChannelTypes 中。
英文:
I have a list of channels like:
type Channels = 'Channel1' | 'Channel2' | ....
and each channel has its own type, so I am using this code:
type BaseTypes = {[key in Channels]: object};
interface ChannelTypes extends BaseTypes {
Channel1: {/* define required data*/},
Channel2: {/* define required data*/},
}
I want to find a way when I add a value to channels to force me to update ChannelTypes, and reject any key in ChannelTypes not defined in Channels
答案1
得分: 0
You can use mapped types and lookup types. First define a type with a list of channels as you did:
type Channels = 'Channel1' | 'Channel2';
Next, define a type that maps channel types to their data, for example:
type ChannelToData = {
Channel1: string;
Channel2: number;
};
And finally, define a type:
type ChannelTypes = {
[Channel in Channels]: ChannelToData[Channel];
};
With this approach, if you add a new type to the union Channels, TypeScript will force you to define a specific data type for it in the type ChannelToData.
英文:
You can use mapped types and lookup types. First define type with list of channels as you did:
type Channels = 'Channel1' | 'Channel2';
Next define type which maps channel type to its data, for example:
type ChannelToData = {
Channel1: string;
Channel2: number;
};
And finally define type:
type ChannelTypes = {
[Channel in Channels]: ChannelToData[Channel];
};
With this approach, if you add new type to union Channels, TypeScript forces you to define specific data type for it in type ChannelToData.
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