英文:
How can I make it so that only the last class interval is closed on the right?
问题
I'm trying to close only the last class interval of this exercise below, but I don't have much knowledge in r and the last interval is opening like all the others.
Code
dados <- c(350, 356, 364, 369, 371, 375, 379, 384, 392,350, 358, 364, 370, 371, 376, 380, 388,351, 359, 365, 370, 372, 376, 380, 391,352, 361, 365, 370, 372, 377, 381, 391,352, 362, 366, 371, 373, 378, 382, 392,354, 363, 368, 371, 374, 378, 383, 392)limites <- seq(min(dados), max(dados), by = 6)classes <- cut(dados, breaks = limites, right = FALSE)freqAbs <- table(classes)tabela <- data.frame(Classe = names(freqAbs),Frequencia = as.numeric(freqAbs))print(tabela)# Classe Frequencia# 1 [350,356) 6# 2 [356,362) 4# 3 [362,368) 7# 4 [368,374) 12# 5 [374,380) 8# 6 [380,386) 6# 7 [386,392) 3
(Note: I have provided the code as requested, but I did not translate the code itself.)
英文:
I'm trying to close only the last class interval of this exercise below, but I don't have much knowledge in r and the last interval is opening like all the others.
Code
dados <- c(350, 356, 364, 369, 371, 375, 379, 384, 392,350, 358, 364, 370, 371, 376, 380, 388,351, 359, 365, 370, 372, 376, 380, 391,352, 361, 365, 370, 372, 377, 381, 391,352, 362, 366, 371, 373, 378, 382, 392,354, 363, 368, 371, 374, 378, 383, 392)limites <- seq(min(dados), max(dados), by = 6)classes <- cut(dados, breaks = limites, right = FALSE)freqAbs <- table(classes)tabela <- data.frame(Classe = names(freqAbs),Frequencia = as.numeric(freqAbs))print(tabela)# Classe Frequencia# 1 [350,356) 6# 2 [356,362) 4# 3 [362,368) 7# 4 [368,374) 12# 5 [374,380) 8# 6 [380,386) 6# 7 [386,392) 3
答案1
得分: 2
From ?cut, there is an argument include.lowest which
> include.lowest: 逻辑值，指示是否应包括等于最低值（或最高值，对于 right = FALSE）的 'breaks' 值。
You can use right = FALSE + include.lowest = TRUE to close the upper bound of the highest interval.
classes <- cut(dados, breaks = limites, right = FALSE, include.lowest = TRUE)
Output
print(tabela)# Classe Frequencia# 1 [350,356) 6# 2 [356,362) 4# 3 [362,368) 7# 4 [368,374) 12# 5 [374,380) 8# 6 [380,386) 6# 7 [386,392] 6
英文:
From ?cut, there is an argument include.lowest which
> include.lowest: logical, indicating if an ‘x[i]’ equal to the lowest (or highest, for right = FALSE) ‘breaks’ value should be included.
You can use right = FALSE + include.lowest = TRUE to close the upper bound of the highest interval.
classes <- cut(dados, breaks = limites, right = FALSE, include.lowest = TRUE)
Output
print(tabela)# Classe Frequencia# 1 [350,356) 6# 2 [356,362) 4# 3 [362,368) 7# 4 [368,374) 12# 5 [374,380) 8# 6 [380,386) 6# 7 [386,392] 6
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