英文:
How do I convert the following type of timestamp to seconds since beginning of unix epoch in PHP
问题
我有以下字符串：
2023-05-10T22:32:21+02:00
我需要将其转换为自1970年1月1日00:00:00 GMT以来的秒数（Unix纪元）
我不关心+02:00部分。我只需要PHP代码将上述内容转换为秒数。我想我可以将T拆分成两个字符串，然后我将得到日期，然后右侧是时间，然后以某种方式解决这个问题，但不确定如何做到这一点。
英文:
I have the following string:
2023-05-10T22:32:21+02:00
I need to convert it to seconds since January 1 1970 00:00:00 GMT (Unix Epoch)
I do not care about the +02:00 section. I just need PHP code to convert the above to a number of seconds. I suppose, I can split the T into 2 strings and then I will have the date and then the time on the right side and then somehow work it out that way but not 100% sure on how to do this.
答案1
得分: 2
以下是翻译好的部分：
你的日期看起来是ISO 8601格式。
使用DateTime::createFromFormat创建一个DateTime对象。有了DateTime对象，你可以调用format方法，其中内置了一个用于表示自Unix纪元以来的秒数的'U'格式选项。
U 自Unix纪元（1970年1月1日00:00:00 GMT）以来的秒数
$dt = DateTime::createFromFormat(DateTimeInterface::ISO8601, '2023-05-10T22:32:21+02:00');
echo $dt->format('U');
结果：1683750741
你可以通过取得的时间戳值，并使用date()函数来从时间戳值创建日期并显示来验证这个工作。
$dt = DateTime::createFromFormat(DateTimeInterface::ISO8601, '2023-05-10T22:32:21+02:00');
$ts = $dt->format('U');
echo date(DATE_RFC2822, $ts);
结果：Wed, 10 May 2023 22:32:21 +0200
英文:
Your date looks to be in the ISO 8601 format.
Make a DateTime Object, with DateTime::createFromFormat. With the DateTime object, you can then call the format method that has a built in 'U' formating option for Seconds since unix epoch.
> U Seconds since the Unix Epoch (January 1 1970 00:00:00 GMT)
<?php
$dt = DateTime::createFromFormat(DateTimeInterface::ISO8601, '2023-05-10T22:32:21+02:00');
echo $dt->format('U');
Result: 1683750741
You can verify this worked by taking the timestamp value you got, and using the date() function to make a date from the timestamp value, and display it.
$dt = DateTime::createFromFormat(DateTimeInterface::ISO8601, '2023-05-10T22:32:21+02:00');
$ts = $dt->format('U');
echo date(DATE_RFC2822, $ts);
Result: Wed, 10 May 2023 22:32:21 +0200
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