英文:
JavaScript filter that returns a match for "A B C" when query is "A C"
问题
给定一个JSON对象数组：
[
{
"id": 1,
"full_name": "约翰·多"
},
{
"id": 2,
"full_name": "约翰·T·多"
},
{
"id": 3,
"full_name": "约翰·T·多"
},
{
"id": 4,
"full_name": "乔恩·道"
}
]
不使用for循环，可以过滤此列表，以便在给定搜索查询为“约翰多”时，返回一个由记录1-3组成的过滤数组作为匹配项，但不包括4。
当搜索查询为“约翰多”时，如果对象集合中出现“约翰”或“多”，则存在匹配。
英文:
Given a JSON array of objects:
`[
{
"id": 1,
"full_name": "John Doe"
},
{
"id": 2,
"full_name": "John T Doe"
},
{
"id": 3,
"full_name": "John T. Doe"
},
{
"id": 4,
"full_name": "Jon Dough"
}
]`
Without doing a for loop, is it possible to filter this list so that given a search query of "John Doe", it returns a filtered array consisting of records 1-3 as matches but not 4?
When the search query is "John Doe" a match exists if either "John" or "Doe" appears in the object collection.
答案1
得分: 1
在你的特定情况下，你可以利用数组对象的.filter函数与正则表达式结合使用。由于你对单词John和Doe感兴趣，正则表达式/\b(?:John|Doe)\b/在字符串上执行，如果字符串中存在John或Doe中的任何一个单词，将返回结果。
let arr = JSON.parse(`[{
"id": 1,
"full_name": "John "
},
{
"id": 2,
"full_name": "John T Doe"
},
{
"id": 3,
"full_name": "John T. Doe"
},
{
"id": 4,
"full_name": "Jon Dough"
}
]`);
console.log(arr.filter(element => element.full_name.match(/\b(?:John|Doe)\b/)));
英文:
In your specific case you can utilize the array objects .filter function in combination with a regular expression. As you're interested in the words John and Doe, the regular expression /\b(?:John|Doe)\b/ executed on a string will return a result if either the word John or Doe are present.
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
let arr = JSON.parse(`[{
"id": 1,
"full_name": "John "
},
{
"id": 2,
"full_name": "John T Doe"
},
{
"id": 3,
"full_name": "John T. Doe"
},
{
"id": 4,
"full_name": "Jon Dough"
}
]`);
console.log(arr.filter(element => element.full_name.match(/\b(?:John|Doe)\b/)));
<!-- end snippet -->
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