英文:
Intersect a set polygons/multi-polygons at once and get the intersected polygon
问题
你可以尝试使用以下代码来获取多边形的交集：
from shapely.geometry import MultiPolygon, Polygon
from shapely.ops import unary_union, polygonize
from itertools import combinations
listpoly = [a.intersection(b) for a, b in combinations(df['geometry'], 2)]
rings = []
for poly in listpoly:
if isinstance(poly, MultiPolygon):
exterior_lines = LineString()
for p in poly:
exterior_lines = exterior_lines.union(p.exterior)
rings.append(exterior_lines)
elif isinstance(poly, Polygon):
rings.append(LineString(list(poly.exterior.coords)))
union = unary_union(rings)
result = [geom for geom in polygonize(union)]
这将给你一个包含多边形交集的列表 result。
英文:
I have a Geopandas data frame with five multi-polygons geometries. Now, I want to intersect all the geometries at once and get the intersected polygon out of it. I tried using unary union and polygonize but this is giving me a list of polygons but I want only one polygon that has the intersection of the set of multi-polygon polygons. How can we intersect a set of multi-polygon or polygons together and get the intersected polygon?
df=
location geometry
1 MULTIPOLYGON (((-0.304766 51.425882, -0.304904...
2 MULTIPOLYGON (((-0.305968 51.427425, -0.30608 ...
3 MULTIPOLYGON (((-0.358358 51.423471, -0.3581 5...
4 MULTIPOLYGON (((-0.357654 51.413925, -0.357604...
rows=[]
listpoly = [a.intersection(b) for a, b in combinations(df['geometry'], 2)]
rings = []
for poly in listpoly:
if type(poly) == MultiPolygon:
exterior_lines = LineString()
for p in poly:
exterior_lines = exterior_lines.union(p.exterior)
rings.append(exterior_lines)
elif type(poly) == Polygon:
rings.append(LineString(list(poly.exterior.coords)))
union = unary_union(rings)
result = [geom for geom in polygonize(union)]
print(result)
MULTILINESTRING((-0.0345 54.900...))
MULTILINESTRING((-0.045 54.200...))
MULTILINESTRING((-0.05 54.650...))
MULTILINESTRING((-0.04 54.750...))
答案1
得分: 1
Shapely的intersect_all函数可以帮助你。
示例代码：
import geopandas as gpd
from matplotlib import pyplot as plt
import shapely
import shapely.plotting
data = [
{"geometry": shapely.box(0, 0, 100, 100), "color": "blue"},
{"geometry": shapely.box(50, 50, 150, 150), "color": "green"},
{"geometry": shapely.box(25, 75, 75, 125), "color": "yellow"},
]
data_gdf = gpd.GeoDataFrame(data)
result = shapely.intersection_all(data_gdf.geometry)
print(result)
data_gdf.plot(color=data_gdf["color"], alpha=0.50)
shapely.plotting.plot_polygon(result, color="red", linewidth=2)
plt.show()
结果是红色的正方形：
英文:
Shapely's intersect_all function can help you out.
Code sample:
import geopandas as gpd
from matplotlib import pyplot as plt
import shapely
import shapely.plotting
data = [
{"geometry": shapely.box(0, 0, 100, 100), "color": "blue"},
{"geometry": shapely.box(50, 50, 150, 150), "color": "green"},
{"geometry": shapely.box(25, 75, 75, 125), "color": "yellow"},
]
data_gdf = gpd.GeoDataFrame(data)
result = shapely.intersection_all(data_gdf.geometry)
print(result)
data_gdf.plot(color=data_gdf["color"], alpha=0.50)
shapely.plotting.plot_polygon(result, color="red", linewidth=2)
plt.show()
Result is the red square:
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