英文:
Reduce & Nested Array
问题
"Subject": "Service 1 - Hound, Roger",
英文:
I am merging two arrays which is working great. But i am showing the data on a calendar and i need an array to be used as a single line.
My Data:
[{"pets": [{"name": "Hound","id": "290dH8Z7nE3kKqMWcsj5"},{"name": "Roger","id": "290dH8Z7nE3kKqMWcsj7"}],"date": [{"date": "2023-05-11"}],"typeofservice": "Service 1","datestart": "2023-05-11","outsideshift": false,"organizationId": "vrpMguv6cwf7L9KLEknR","AddressLine1": "7j2UsMaCI1ehnHl5FbMf",}]
const partialDetails = a3.reduce((res, item) => {res.push({ Subject: item.typeofservice , StartTime: item.datestart, IsAllDay: true, CategoryColor: "#1aaa55", Description: "Address: " + item.AddressLine1 })return res;}, []);
Results Currently
[{"Subject": "Service 1","StartTime": "2023-05-11","IsAllDay": true,"CategoryColor": "#1aaa55","Description": "Address: AddressLine1Address"}]
Wanted result the array in pets to be able to go into the subject line. There could be 1 there could be many.
[{"Subject": "Service 1 - Hound, Roger","StartTime": "2023-05-11","IsAllDay": true,"CategoryColor": "#1aaa55","Description": "Address: AddressLine1Address"}]
Ive tried map inside but that creates a new line
答案1
得分: 1
这是您提供的代码的翻译部分：
const a = [{"pets": [{"name": "Hound","id": "290dH8Z7nE3kKqMWcsj5"},{"name": "Roger","id": "290dH8Z7nE3kKqMWcsj7"}],"date": [{"date": "2023-05-11"}],"typeofservice": "Service 1","datestart": "2023-05-11","outsideshift": false,"organizationId": "vrpMguv6cwf7L9KLEknR","AddressLine1": "7j2UsMaCI1ehnHl5FbMf",}]const partialDetails = a.reduce((res, item) => {const subject = item.typeofservice + ' - '+ item.pets.map(pet=>pet.name).join( ', ');res.push({ Subject: subject , StartTime: item.datestart, IsAllDay: true, CategoryColor: "#1aaa55", Description: "Address: " + item.AddressLine1 })return res;}, []);console.log(partialDetails)
请注意，这只是提供了代码的翻译，不包含其他内容。
英文:
You can try:
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
const a = [{"pets": [{"name": "Hound","id": "290dH8Z7nE3kKqMWcsj5"},{"name": "Roger","id": "290dH8Z7nE3kKqMWcsj7"}],"date": [{"date": "2023-05-11"}],"typeofservice": "Service 1","datestart": "2023-05-11","outsideshift": false,"organizationId": "vrpMguv6cwf7L9KLEknR","AddressLine1": "7j2UsMaCI1ehnHl5FbMf",}]const partialDetails = a.reduce((res, item) => {const subject = item.typeofservice + ' - '+ item.pets.map(pet=>pet.name).join( ', ');res.push({ Subject: subject , StartTime: item.datestart, IsAllDay: true, CategoryColor: "#1aaa55", Description: "Address: " + item.AddressLine1 })return res;}, []);console.log(partialDetails)
<!-- end snippet -->
答案2
得分: 0
const partialDetails = data.reduce((res, item) => {
res.push({ Subject: ${item.typeofservice} - ${item.pets.map((el) => el.name).join(', ')} , StartTime: item.datestart, IsAllDay: true, CategoryColor: "#1aaa55", Description: "Address: " + item.AddressLine1 })
return res;
}, []);
英文:
const partialDetails = data.reduce((res, item) => {res.push({ Subject: `${item.typeofservice} - ${item.pets.map((el)=>el.name).join(', ')}` , StartTime: item.datestart, IsAllDay: true, CategoryColor: "#1aaa55", Description: "Address: " + item.AddressLine1 })return res;}, []);
basically the same as previous answer using map and join for the names.
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论