英文:
Oracle Apex Checkbox when read only showing session violation error
问题
I have a page item which is a checkbox: P1_EMPID
它以前是可编辑的，但现在我需要在单击另一个按钮时对其进行检查。
我将P1_EMP_ID属性设置为-> 只读-> 始终
维护会话状态-> 始终
会话状态保护无限制。
在按钮上-> 我设置了动态操作的值，将P1_EMPID设置为Y以检查复选框。当我单击按钮时，分配发生，但当我使用页面上的更新按钮进行操作时，它抛出以下错误：
会话状态保护违规：这可能是由受保护的页面项引起的。
但项目的值受保护设置为否。
可能的原因是什么？
英文:
I have a page item which is a checkbox : P1_EMPID
It was editable previously but now i have requirement to add another button on click of which this would be checked.
I set P1_EMP_ID property-> Readonly-> Always
Maintain Session State-> Always
Session state protection unrestricted.
On the button-> I have set value dynamic action which sets P1_EMPID TO Y to check the checkbox. When i click button assignment happens, But when i proceed using update button in page it throws following erro:
Session state protection violation: This may be caused by protected page item.
But value protected for the item is set to No.
What could be the cause?
答案1
得分: 0
这是预期行为。“只读”不仅控制项目的显示方式，还保护项目免受更改。服务器确保项目确实是“只读”，并且浏览器无法在服务器上更改项目的值。解决方法是不使用“只读”属性，而是使用css类“apex_disabled”。
英文:
That is expected behaviour. “Read Only” does not only control how an item is displayed; it also protects the item against changes. The server makes sure that the item is indeed “Read Only”, and that the browser is not able to change the item value on the server. The solution to not use the "Read Only" attribute but use the css class "apex_disabled"
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论