英文:
how would i use grep to find words in a file that start and end with specified letter?
问题
I want to match all the words in a file that start with "s" and end with "n" so i tried this before
grep "\bs.*n\b"
but it contain part of the line and i need just words
英文:
I want to match all the words in a file that start with "s" and end with "n" so i tried this before
grep "\bs.*n\b"
but it contain part of the line and i need just words
答案1
得分: 2
Here is the translated content:
像这样，假设单词可以由2个字符到∞个字符组成：
grep -oE ''\bs[[:alpha:]]*n\b'' file
-o显示匹配的部分-E用于使用ERE正则表达式风格
正则表达式的匹配如下：
| 节点 | 说明 |
|---|---|
\b |
单词字符（\w）与非单词字符之间的边界锚点 |
s |
s |
[[:alpha:]]* |
任何字符：字母（零次或多次） |
n |
n |
\b |
单词字符（\w）与非单词字符之间的边界锚点 |
示例：
$ cat file
sn
aaaaa soon sss saaaaan
bbb siiiiiiiiin xxx sXXXXXXn
$ grep -oE ''\bs[[:alpha:]]*n\b'' file
希望这能帮助您理解代码和正则表达式的含义。
英文:
Like this, assuming words can be from 2 characters to ∞:
grep -oE '\bs[[:alpha:]]*n\b' file
-odisplay only matching part-Eis to useEREregex flavor
The regular expression matches as follows:
| Node | Explanation |
|---|---|
\b |
the boundary anchor between a word char (\w) and something that is not a word char anchor |
s |
s |
[[:alpha:]]* |
any character of: letters (zero or more times) |
n |
n |
\b |
the boundary anchor between a word char (\w) and something that is not a word char anchor |
Example:
$ cat file
sn
aaaaa soon sss saaaaan
bbb siiiiiiiiin xxx sXXXXXXn
<p>
$ grep -oE '\bs[[:alpha:]]*n\b' file
<p>
sn
soon
saaaaan
siiiiiiiiin
sXXXXXXn
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