英文:
Get quotients and remainder from division of floats
问题
The Pythonic approach to getting quotients and remainders from division of floats can be achieved using the built-in math.modf function. Here's an example:
import math
def aPythonOperator(a, b):
quotient, remainder = math.modf(a / b)
return quotient, remainder
result = aPythonOperator(8, 3)
print(f'aPythonOperator(8, 3) = {result}')
This will give you the desired output:
aPythonOperator(8, 3) = (2.0, 0.6666666666666665)
The math.modf function separates the integer part (floored division) and the fractional part of the division result, providing the desired behavior without rounding the remainder.
英文:
What is the Pythonic approach to getting a quotients and remainder from division of floats? So taking 8 divided by 3 which is 2.66666666666
so I want:
aPythonOperator(8,3) = 2.0, 0.66666666666
but I cannot find a clean way of doing this without the remainder being rounded.
For completeness the Python division operators are:
import math
a = 8.0
b = 3.0
print(f'Division:{a/b}')
print(f'Floored division: {a//b}')
print(f'Modulo: {a%b}')
print(f'Remainder: {math.remainder(a,b)}') # rounds to int and yields -1 (?)
print(f'Divmod: {divmod(a, b)}')
which gives:
Division:2.6666666666666665
Floored division: 2.0
Modulo: 2.0
Remainder: -1.0
These don't help, but I expected the Divmod function to work. However, Divmod rounds the quotient to an int:
print(f'Divmod: {divmod(a, b)}')
Divmod: (2.0, 2.0)
I can get the behaviour I want by creating my own version of the Divmod function:
def hackDivmod(a,b):
#HACK
Div = (a/b)
floredDiv = (a//b)
return floredDiv, Div-floredDiv
This works as desired:
HackDivmod: (2.0, 0.6666666666666665)
But is there a better way do doing this using built in functions or operators?
答案1
得分: 3
I guess you want to use math.modf() combined with native division
>>> import math
>>> math.modf( 8 / 3)
(0.6666666666666665, 2.0)
英文:
I guess you want to use math.modf() combined with native division
>>> import math
>>> math.modf( 8 / 3)
(0.6666666666666665, 2.0)
答案2
得分: 1
以下是翻译好的部分：
def divfract(a, b):
return a // b, (a % b) / b
这段代码返回与您的“hack”函数相同的结果（实际上也完全可以），包括负数（例如 divfract(-8, 3) == (-3, 0.333...)），而 math.modf 则是另一种方式 (-2, -0.666...)。（有关计算余数的不同方法，请参考此链接）
英文:
You could do
def divfract(a, b):
return a // b, (a % b) / b
This returns the same result as your 'hack' function (which is actually also perfectly fine), including for negative numbers (e.g divfract(-8, 3) == (-3, 0.333...)), whereas math.modf rounds the other way (-2, -0.666...). (There are different ways to calculate a remainder)
答案3
得分: 0
你可以使用 math.modf() 函数来获取两个分开的部分。它是一个内置方法，用于将数字拆分为整数和小数部分。你可以使用以下自定义的 myDivMod() 函数来实现如下功能：
import math
def myDivMod(myParam, myDiv):
fraction, wholeNum = math.modf( myParam / myDiv)
return fraction, wholeNum
a,b = myDivMod(8,3)
print(a,b) # 输出是 0.6666666666666665, 2.0
希望这解决了你的问题。
英文:
You can use the math.modf() to get two separate portions. It is a built in method to split a number into integer and decimal parts. You can use the following custom myDivMod() function is order to make it work as following:
import math
def myDivMod(myParam, myDiv):
fraction, wholeNum = math.modf( myParam / myDiv)
return fraction, wholeNum
a,b = myDivMod(8,3)
print(a,b) # output is 0.6666666666666665, 2.0
I hope this solves your issue
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