英文:
Is it possible to only retrieve the latest/last value when using the request.security_lower_tf function in PineScript v5?
问题
Here's the translated code portion you requested:
这是我用来获取第二时间框架数值的代码：
secHighArr = request.security_lower_tf(syminfo.tickerid, "1S", high)
aTable = table.new(position.top_center, 2, 2)
table.cell(aTable, 1, 1, str.tostring(secHighArr))
如果我在5分钟时间框架上，显然会返回在5分钟周期内所有第二数值，有可能只获取最新/最后一个 secHighArr 值，而不是所有值吗？
英文:
So here’s the code that I’m using to retrieve the second timeframes values:
secHighArr = request.security_lower_tf(syminfo.tickerid, “1S”, high)
aTable = table.new(position.top_center,2,2)
table.cell(aTable, 1,1, str.tostring(secHighArr))
If I’m on a 5 minute timeframe this is obviously returning all the second values in the 5 minute period, is it possible to only retrieve the latest/last secHighArr value instead of all of them?
答案1
得分: 0
request.security_lower_tf 返回一个数组。您无法仅从此调用中获取一个值。
request.security_lower_tf(symbol, timeframe, expression, ignore_invalid_symbol, currency) → 数组<类型>
但是，由于它是一个数组，您可以使用以下方式获取该数组的最后一个值：
len = secHighArr.size()
float last_val = (len > 0) ? array.get(secHighArr, len - 1) : na
英文:
request.security_lower_tf returns an array. You cannot get only one value out of this call.
request.security_lower_tf(symbol, timeframe, expression, ignore_invalid_symbol, currency) → array<type>
However, since it is an array, you can get the last value of that array with:
len = secHighArr.size()
float last_val = (len > 0) ? array.get(secHighArr, len - 1) : na
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