问题

I am a beginner and don't know what I've done wrong, help.
我是新手，不知道我做错了什么，请帮忙。

I tried multiple things, but all didn't work.
我尝试了多种方法，但都没有成功。

答案1

得分: 1

所以这里有几个问题。你声明了一个整数类型的变量p，并赋值为`p=0`，但你在while循环中将其用作布尔值，同时你在`if else`语句中试图将其用作字符串输入。考虑使用更多的变量来达到你的目的。

首先，将`p=0`替换为`p=True`。让它成为你的循环标志。

其次，在循环内部，创建一个新的变量，比如q。
`q = int(input(这里是你的文本))`

第三，对于if else条件，由于我们有了一个整数类型的q，可以这样做：

```python
if q == 1:
    print('你选择了1。')
elif q == 2:
    print('你选择了2。') #以此类推

最终你的代码可能看起来像这样：

def 菜单():
    p = True
    while p:
        q = int(input('输入值：'))
        if q == 1:
            print('你选择了1')
        elif q == 2:
            print('你选择了2')
        elif q == 3:
            print('你选择了3')

菜单()

<details>
<summary>英文:</summary>

So there are a couple of things going wrong here. You have declared a variable p as integer type with `p=0`, yet you use it like a bool in the while loop and you are trying to use it like a string input in the `if else` statements. Consider using more variables for your purpose.

First, replace `p=0` with `p=True`. Let this be your loop flag.

Second, inside the loop, make a new variable say q.
`q = int(input(`Your text here`))`

Third, for the if else condition, since we have an integer type q, do this:

if q == 1:
print('You selected 1.')
elif q == 2:
print('You selected 2.') #and so on

Ultimately your code might look something like this:

def menu():
p = True
while p:
q = int(input('Enter the value:'))
if q == 1:
print('You selected 1')
elif q == 2:
print('You selected 2')
elif q == 3:
print('You selected 3')

menu()

</details>



# 答案2
**得分**: 1

You can use "while True," which is equivalent to what you wrote. You can use a list with the values you need, and if your entered information is in that list, then we display the entered information, and if not, then again.

```python
def menu3():
    while True:
        q = int(input('输入文本1：'))
        q_true = [1, 2, 3]
        if q in q_true:
            print(f'文本2：{q}')

menu3()

def menu3():
    while True:
        q = int(input('*you text 1* '))
        q_true = [1, 2, 3]
        if q in q_true:
            print(f'*you text 2* {q}')

menu3()