英文:
Using Discord.NET, how do i record an interaction response into a variable?
问题
我最近遇到了一个问题，即无法使用典型的方法将交互响应记录到变量中以供以后处理，因为RespondAsync是一个async Task，不提供任何消息类型的输出。
我尝试在官方API和向AI提问中搜索，但没有找到任何有效的答案。
我还尝试了
var msg = await Context.Interaction.RespondAsync(embed: Completed.Build()).MethodOrProperty;
//以及
var msg = (await Context.Interaction.RespondAsync(embed: Completed.Build()) as AnyMessageType);
由于非常明显的原因，这两种方法都不起作用。
英文:
I recently stumbled across the issue that an interaction response cannot be recorded into a variable for latter handling with a typical method, var msg = await Context.Interaction.RespondAsync(embed: Completed.Build()); because RespondAsync is an async Task not giving any message type output.
I tried searching the official API as well as asking AI but haven't found any valid answer.
Also i tried
var msg = await Context.Interaction.RespondAsync(embed: Completed.Build()).MethodOrProperty;
//as well as
var msg = (await Context.Interaction.RespondAsync(embed: Completed.Build()) as AnyMessageType);
which didn't work for pretty obvious reasons.
答案1
得分: 2
如果您查看源代码，您会注意到评论最近已更改：
从：
> 代表异步发送操作以传递消息的任务。 任务结果包含发送的消息。
到：
> 代表异步发送操作以传递消息的任务。
此更改的拉取请求表示XML文档是一个错误，已经修复。
似乎没有包含消息的结果。
英文:
If you look at the source, you will notice that the comment has recently changed:
From:
> A task that represents an asynchronous send operation for delivering the message. The task result contains the sent message.
To:
>A task that represents an asynchronous send operation for delivering the message.
The Pull Request for this change says the XML documentation was a mistake and has been fixed.
It seems there is no result containing the message.
答案2
得分: 0
发现有 Context.Interaction.GetOriginalResponseAsync。希望对有相同问题的人有所帮助。
英文:
Found out that there is Context.Interaction.GetOriginalResponseAsync. Hope that helps anybody with the same issue.
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