英文:
I typed is digit function for user input, but when I enter an alphabet, it accepts the value
问题
我创建了一个通过ID搜索客户姓名的代码。我使用isdigit函数来确保用户输入一个数字，但是当我输入一个字母时，它也接受了。为什么会这样？
英文:
IDcheck = input("Enter The Customer ID ")
if IDcheck.isdigit :
print("Your ID is Being Searched")
elif IDcheck.isalpha :
print("IDs Only Contains Numbers")
I made a code to search customers names by ID . typed isdigit function to make sure the user enters a number
but when I type a letter, it does accept it. why
答案1
得分: 1
String.isdigit 是一个函数。
当解释器执行这一行代码 if IDcheck.isdigit: 时，它会检查是否存在一个名为 IDcheck.isdigit 的函数或变量。IDcheck.isdigit 存在，并返回 True。对于 IDcheck.isalpha 也是一样的情况。
要修复这个问题，将 IDcheck.isdigit 和 IDcheck.isalpha 改为 IDcheck.isdigit() 和 IDcheck.isalpha()，通过添加括号，如下所示：
IDcheck = input("Enter The Customer ID ")
if IDcheck.isdigit():
print("Your ID is Being Searched")
elif IDcheck.isalpha():
print("IDs Only Contains Numbers")
(Note: I have removed the HTML entities for quotation marks in the code for clarity.)
英文:
String.isdigit is a function.
When the interpreter executes the line if IDcheck.isdigit: it checks if a function or variable called IDcheck.isdigit exists. IDcheck.isdigit exist and it returns True. The same applies to IDcheck.isalpha.
To fix this: change IDcheck.isdigit and IDcheck.isalpha to IDcheck.isdigit() and IDcheck.isalpha() by adding parentheses, as in:
IDcheck = input("Enter The Customer ID ")
if IDcheck.isdigit():
print("Your ID is Being Searched")
elif IDcheck.isalpha():
print("IDs Only Contains Numbers")
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