英文:
I cant get array value from my server responce
问题
I have translated the code portion for you:
我通过服务器收到一个字典响应。console.log(responce) 返回以下内容：{"filters":{"Facture": ["Магма (Тычок)","Тонкий кирпич","Гладкий","Крафт","Магма"],"Color": ["Беж","Черный","Амстердам","Лондон Брик","Мюнхен","Сити Брик"],"Name": ["Облицованный кирпич стандартный пустотелый","Тонкий колотый с ф. 180/11"]}}但是当我尝试使用以下代码访问值时：console.log(xhr.responseText);const response = xhr.responseText;console.log(response);const myObj = JSON.parse(response);console.log(myObj);var names = myObj.Name.map(name => name.trim());var types = myObj.Facture.map(type => type.trim());var colors = myObj.Color.map(color => color.trim());console.log(names);console.log(types);console.log(colors);
如果在脚本内部创建此对象，它可以正常工作，但是当我通过响应获取对象时，它不起作用。我尝试了几乎所有方法，包括更改服务器发送的数据和使用不同的代码访问值，但仍然返回undefined。请帮助我获取值...
英文:
I have my server respond me with an dictionary.
The console.log(responce) returns this:
{"filters":{"Facture": ["Магма (Тычок)","Тонкий кирпич","Гладкий","Крафт","Магма"],"Color": ["Беж","Черный","Амстердам","Лондон Брик","Мюнхен","Сити Брик"],"Name": ["Облицованный кирпич стандартный пустотелый","Тонкий колотый с ф. 180/11"]}}
But when i try to access the value with this code:
console.log(xhr.responseText);const response = xhr.responseText;console.log(response);const myObj = JSON.parse(response);console.log(myObj);var names = myObj.Name.map(name => name.trim());var types = myObj.Facture.map(type => type.trim());var colors = myObj.Color.map(color => color.trim());console.log(names);console.log(types);console.log(colors);
It returns undefined in the console. Please help me get the value....
The only clue that i got, that if i create this object inside of my script it works correct, but doesnt work when i get the object through the responce
I tried literally everything:
Changing the data i send by the server
Accessing the value with different code...
答案1
得分: 1
将这行代码更改为：
const myObj = JSON.parse(response).filters;
因为你要查找的值似乎在属性filters内。
编辑
请注意，评论中提到服务器返回的是"{...}"而不是{...}，因此我们不得不进行双重解析：
const myObj = JSON.parse(JSON.parse(response)).filters;
如果你有服务器/后端的控制权，更好的解决方案是在那里进行修复。
英文:
Change this line:
const myObj = JSON.parse(response);
to
const myObj = JSON.parse(response).filters;
since the values you look for seem to be inside the property filters.
Edited
See, comments - it turns out the server returned "{...}" rather than {...} so we hade to double parse it:
const myObj = JSON.parse(JSON.parse(response)).filters;
A better solution if you have control of the server/backend would be to fix this there.
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