问题

class meow() : InputConnection {
     override fun getTextBeforeCursor(before: Int, after: Int): CharSequence? {
       return super.getTextBeforeCursor(before, after)
     }
}

但为什么继承接口既需要重写，又说“无法直接访问此内容”？
上述错误的原因

这张图片显示了错误。一个是因为需要重写更多内容（是的），另一个是为什么这个重写“无法直接访问抽象成员”（为什么？）。

而且不仅是“为什么”，还要如何正确继承具有这个特性的接口？

<details>
<summary>英文:</summary>

class meow(): InputConnection{
override fun getTextBeforeCursor(before:Int,after:Int):CharSequence?{
return super.getTextBeforeCursor(before,after)
}

}

but whai does inheriting an interface both require overriding, and say `cannot access this directly'?
[what the above errors][1]

This image is the errors from this.  One for there being more stuff in need of override (yes) and another how this override `can't access abstract member directly` (why?).

And not just 'why', but hao inherit an interface with this aspect correctly?


  [1]: https://i.stack.imgur.com/Lb0zc.png

</details>


# 答案1
**得分**: 0

你不能调用*抽象*函数，因为它没有定义在被调用时要执行什么操作。

如果一个接口声明一个没有默认实现的函数，那么它就是*抽象*的。

在这种情况下，显然InputConnection类没有为这个函数定义默认实现。`InputConnection.getTextBeforeCursor()`是抽象的，因此你不能使用`super.getTextBeforeCursor()`来调用它。

要正确执行此操作，你需要自己定义这个函数的内容以及在没有依赖于`super`版本的情况下它的行为。

<details>
<summary>英文:</summary>

You cannot call an *abstract* function because it has no definition of what to do when called.

If an interface declares a function without any default implementation, then it is *abstract*.

In this case, evidently the InputConnection class does not define a default implementation for this function. `InputConnection.getTextBeforeCursor()` is abstract, so you cannot call it using `super.getTextBeforeCursor()`.

To do this correctly, it is up to you to define the content of this function and how it will behave without any reliance on a `super` version of this function.

</details>