问题

团队，我有一个用例，需要在循环时将数组的余下部分保存到新数组中，新数组应该包含除了循环元素以外的所有元素。

$ a=(1 2 3 4 5)
$ b=()

for index in ${!a[@]}
do
b=(${a[@]:0:index} ${a[@]:index+1}) # 这样编写代码可以使其正常工作
echo ${b[@]}
done

每次迭代的预期循环值。

1 2 3 4
1 2 3 5
1 2 4 5
1 3 4 5
2 3 4 5

<details>
<summary>英文:</summary>

Team, I have a use case to save remainder of array into new array while looping on its indices and new array should have all elements except the looped element.

$ a=(1 2 3 4 5)
$ b=()

for index in ${!a[@]}
do
b=(a - a[$index]) #how would i code his that it works ?
echo ${b[@]}
done

expected loop values for each iteration.

1 2 3 4
1 2 3 5
1 2 4 5
1 3 4 5
2 3 4 5

</details>


# 答案1
**得分**: 2

只保留简单。

    b=("{$a[@]}")
    取消设置 b[$index]

<details>
<summary>英文:</summary>

Just be simple.

    b=(&quot;${a[@]}&quot;)
    unset b[$index]

</details>



# 答案2
**得分**: 0

```bash
#!/bin/bash
a=(1 2 3 4 5)
b=()

for index in "${!a[@]}" ; do
    b=("${a[@]:0:index}")

    # 这里应该是 "${a[@]:index+1:${#a[@]}-index-1}",
    # 但结果是相同的。
    b+=("${a[@]:index+1:${#a[@]}}")

    echo "${b[@]}"
done

#!/bin/bash
a=(1 2 3 4 5)
b=()

for index in "${!a[@]}" ; do
    b=("${a[@]:0:index}")

    # This should be "${a[@]:index+1:${#a[@]}-index-1}",
    # but the result is the same.
    b+=("${a[@]:index+1:${#a[@]}}")

    echo "${b[@]}"
done