英文:
Turning a 1D array and a variable into a new 2D array
问题
我是新手程序员，对 TypeScript 中的数组感到困惑。
我有以下变量：
let nameList: string[] = ['a', 'b', 'c', 'd'];
let postId: number = 1;
我的目标是创建一个新的二维数组：
let newList: (string | number)[][] = [];
其中
newlist = [
[a,1],
[b,1],
[c,1],
[d,1]
]
我尝试过：
for (let i: number = 0; i < userList.length; i++) {
newList[i][0].push(userList[i]);
newList[i][1].push(insertID);
}
还尝试过
for (let i: number = 0; i < userList.length; i++) {
newList[i][0] = userList[i];
newList[i][1] = insertID;
}
有人能帮我解决这个问题吗？
非常感谢！
英文:
Im new to programming and Im struggling with arrays in typescript.
I have the following variables:
let nameList: string[] = ['a', 'b', 'c', 'd'];
let postId: number = 1;
My goal is to create a new 2D array:
let newList: (string | number)[][] = [];
where
newlist = [
[a,1],
[b,1],
[c,1],
[d,1]
]
I've tried:
for (let i: number = 0; i < userList.length; i++) {
newList[i][0].push(userList[i]);
newList[i][1].push(insertID);
}
Also
for (let i: number = 0; i < userList.length; i++) {
newList[i][0] = userList[i];
newList[i][1] = insertID;
}
Can someone help me with this?
Much apprerciated!
答案1
得分: 0
const new2dArray: [string, number][] = nameList.map((name) => [name, postId]); 的中文翻译是：
const new2dArray: [string, number][] = nameList.map((name) => [name, postId]);
英文:
const new2dArray: [string, number][] = nameList.map((name) => [name, postId]);
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