英文:
Set a unique value for the first duplicate, and a default value for subsequent duplicates of the same number
问题
对于每个PAN号码的重复项,将第一个重复项设置为特定的REMARKS值,将所有后续重复项设置为默认值。
以下是期望的输出:
| PAN | REMARKS | 
|---|---|
| 11211 | The One | 
| 11211 | 0 | 
| 11211 | 0 | 
| 11211 | 0 | 
| 13111 | The One | 
| 13111 | 0 | 
| 13111 | 0 | 
| 13111 | 0 | 
英文:
For each PAN number duplicates, set a specific REMARKS value for the first duplicate and a default value for all subsequent duplicates.
Here is the expected output
| PAN | REMARKS | 
|---|---|
| 11211 | The One | 
| 11211 | 0 | 
| 11211 | 0 | 
| 11211 | 0 | 
| 13111 | The One | 
| 13111 | 0 | 
| 13111 | 0 | 
| 13111 | 0 | 
Here are some queries I tried but they didn't work.
// First Query
UPDATE YourTableName
SET REMARKS = CASE 
                 WHEN (
                    SELECT COUNT(*)
                    FROM YourTableName AS T2
                    WHERE T2.PAN = YourTableName.PAN AND T2.PAN <> ''
                 ) = 0 THEN 'The One'
                 ELSE '0'
             END;
// second query
WITH CTE AS (
    SELECT PAN, ROW_NUMBER() OVER (PARTITION BY PAN ORDER BY (SELECT 0)) AS RowNum
    FROM YourTableName
)
UPDATE YourTableName
SET REMARKS = CASE WHEN CTE.RowNum = 1 THEN 'The One' ELSE '0' END
FROM YourTableName 
INNER JOIN CTE ON YourTableName.PAN = CTE.PAN
//Third Query
UPDATE x
SET x.Total_Outstanding = '0',x.Total_exposure='0'
FROM (
      SELECT ROW_NUMBER() OVER (
      PARTITION BY PAN_NO
      ORDER BY PAN_NO
   ) row_num,
   [Family_Name]
      ,[Client_Name]
      ,[Account_Name]
      ,[Account_Id]
      ,[Held_Away]
      ,[Prospect]
      ,[Product_Name]
      ,[Asset_Name]
      ,[AMC_Short_Name]
      ,[Total_exposure]
      ,[Instrument_Category_Name]
      ,[Instrument_Name]
      ,[ISIN]
      ,[BOS_Code]
      ,[Total_Outstanding]
      ,[PAN_NO]
      ,[Folio]
      ,[Concatenate1]
      ,[Units]
      FROM dtpandata
      ) x where x.row_num > 1
答案1
得分: 0
你可以使用 CTE 和 WINDOW FUNCTION(LAG,count) 来解决这个问题
;WITH CTE AS (
    select REMARKS
			,LAG(PAN,1) over (partition by PAN ORDER BY (SELECT 0)) as lPAN
			,count(*) over (partition by PAN ORDER BY (SELECT 0)) as  countPAN
			from Tn
)
UPDATE T
SET REMARKS = case when lPAN is null and countPAN>1 then 'The One' else '0'   end
FROM CTE  T
你可以使用以下语句创建插入基础数据
drop table if exists Tn
create table Tn(ID int,PAN	int,Client_Name varchar(100),REMARKS  varchar(100))
insert into Tn (Id,PAN,Client_Name) values( 1,11211,'aa1')	
insert into Tn (Id,PAN,Client_Name) values(2,11211,'aa2')		
insert into Tn (Id,PAN,Client_Name) values(3,11211,'aa3')		
insert into Tn (Id,PAN,Client_Name) values(4,11211,'aa4')		
insert into Tn (Id,PAN,Client_Name) values(5,13111,'aa4')		
insert into Tn (Id,PAN,Client_Name) values(6,13111,'aa5')		
insert into Tn (Id,PAN,Client_Name) values(7,13111,'aa5')		
insert into Tn (Id,PAN,Client_Name) values(8,13111,'aa6')		
英文:
You can use CTE and WINDOW FUNCTION(LAG,count) to solve the problem
;WITH CTE AS (
    select REMARKS
			,LAG(PAN,1) over (partition by PAN ORDER BY (SELECT 0)) as lPAN
			,count(*) over (partition by PAN ORDER BY (SELECT 0)) as  countPAN
			from Tn
)
UPDATE T
SET REMARKS = case when lPAN is null and countPAN>1 then 'The One' else '0'   end
FROM CTE  T
You can create insert base data with the following statements:
drop table if exists Tn
create table Tn(ID int,PAN	int,Client_Name varchar(100),REMARKS  varchar(100))
insert into Tn (Id,PAN,Client_Name) values( 1,11211,'aa1')	
insert into Tn (Id,PAN,Client_Name) values(2,11211,'aa2')		
insert into Tn (Id,PAN,Client_Name) values(3,11211,'aa3')		
insert into Tn (Id,PAN,Client_Name) values(4,11211,'aa4')		
insert into Tn (Id,PAN,Client_Name) values(5,13111,'aa4')		
insert into Tn (Id,PAN,Client_Name) values(6,13111,'aa5')		
insert into Tn (Id,PAN,Client_Name) values(7,13111,'aa5')		
insert into Tn (Id,PAN,Client_Name) values(8,13111,'aa6')		
	
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