问题

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我在python测试函数中有多个assert语句，如下所示：
```python
def test_function():
    assert A.a == 1
    assert B.b == 2
    assert C.c == 3
    assert D.d == 4
    assert E.e == 5
    assert F.f == 6
    assert G.g == 7

我只想以一种合适的动态方式编写此测试函数，所以我尝试了以下代码：

import unittest
def test_function():
    x = {"a": A.a, "b": B.b, "c": C.c, "d": D.d, "e": E.e, "f": F.f, "g": G.g}
    y = {"a": 1, "b": 2, "c": 3, "d": 4, "e": 5, "f": 6, "g": 7}
    for k, v in x.items():
        for k1, v1 in y.items():
            if k == k1 and v == v1:
                assert v == v1

但我发现这也不是一个好方法，因为不需要if语句，但如果我删除if语句会出错。

我正在寻找一种更好的方法来合并这些assert语句。

编辑： 简单地说，我可以将所有的A.a, B.a....和1, 2, ..放在列表中，如下所示：

l1 = [A.a, B.b, C.c, D.d, E.e, F.f, G.g]
l2 = [1, 2, 3, 4, 5, 6, 7]

然后希望生成assert语句，如下所示：

assert l1[0] == l2[0]
assert l1[1] == l2[1]
# 以此类推，无需使用任何内置函数

<details>
<summary>英文:</summary>

I have a multiple assert statement in a python test function as below:

def test_function():
assert A.a == 1
assert B.b == 2
assert C.c == 3
assert D.d == 4
assert E.e == 5
assert F.f == 6
assert G.g == 7

I just want to write this test function in a proper dynamic way, so I have tried:

import unittest
def test_function():
x = {"a": A.a, "b": B.b, "c": C.c, "d": D.d, "e": E.e, "f":F.f, "g":G.g}
y = {"a": 1, "b": 2, "c": 3, "d": 4, "e": 5, "f":6, "g":7}
for k, v in x.items():
for k1, v1 in y.items():
if k == k1 and v==v1:
assert v == v1

But I have found that is also not a good way, because `"if"` is not required, but if I remove the "if" statement an error occurs.

I'm looking for a better way to merge this `assert` statements.
___
**EDIT:** Simply I can put all `A.a, B.a....` and `1, 2, ..` in the list like below, 

    l1 = [A.a, B.b, C.c, D.d, E.e, F.f, G.g]
    l2 = [1, 2, 3, 4, 5, 6, 7]

And from it want to make assert statement, 

    assert l1[0] == l2[0]
    assert l1[1] == l2[1].......
**without any inbuilt function**

</details>


# 答案1
**得分**: 2

如果您正在使用 `unittest`，您需要将测试放在一个继承自 `unittest.TestCase` 的类中。然后，您可以使用 `unittest.TestCase` 中的 `assertEqual()` 方法：

```python
import unittest

class MyTests(unittest.TestCase):
    def test_function(self):
        x = {"a": A.a, "b": B.b, "c": C.c, "d": D.d, "e": E.e, "f": F.f, "g": G.g}
        y = {"a": 1, "b": 2, "c": 3, "d": 4, "e": 5, "f": 6, "g": 7}
        self.assertEqual(x, y)

另一方面，如果您正在使用 pytest，您可以简单地使用 assert x == y：

def test_function():
    x = {"a": A.a, "b": B.b, "c": C.c, "d": D.d, "e": E.e, "f": F.f, "g": G.g}
    y = {"a": 1, "b": 2, "c": 3, "d": 4, "e": 5, "f": 6, "g": 7}
    assert x == y

import unittest

def MyTests(unittest.TestCase):
    def test_function(self):
        x = {"a": A.a, "b": B.b, "c": C.c, "d": D.d, "e": E.e, "f":F.f, "g":G.g}
        y = {"a": 1, "b": 2, "c": 3, "d": 4, "e": 5, "f":6, "g":7}
        self.assertEqual(x, y)

def test_function():
    x = {"a": A.a, "b": B.b, "c": C.c, "d": D.d, "e": E.e, "f":F.f, "g":G.g}
    y = {"a": 1, "b": 2, "c": 3, "d": 4, "e": 5, "f":6, "g":7}
    assert x == y

答案2

得分: 0

以下是翻译好的部分：

如果您想以适当的动态方式执行测试，而不使用Python的unittest，您可以使用以下的test_function()：

def test_function():
    l1 = [A.a, B.b, C.c, D.d, E.e, F.f, G.g]
    l2 = [1, 2, 3, 4, 5, 6, 7]
    for i in range(0, len(l1)):
        assert l1[i] == l2[i]

先前的代码使用了您问题编辑部分中定义的列表l1和l2。

此外，我认为使用unittest模块更可取，在这种情况下，您可以参考@Code-Apprentice的答案。

def test_function():
    l1 = [A.a, B.b, C.c, D.d, E.e, F.f, G.g]
    l2 = [1, 2, 3, 4, 5, 6, 7]
    for i in range(0, len(l1)):
        assert l1[i] == l2[i]