python - selenium webdriver wait until condition met

i want to make the selenium webdriver to click something when the condition met, and to refresh the page if the condition not met, is this the right code for the condition met or not? i need enlightenment, because this code isn't executed properly

wait = ui.WebDriverWait(driver, 5)
wait_new = wait.until(lambda driver: driver.find_element(By.NAME, 'create_it'))
wait_old = wait.until(lambda driver: driver.find_element(By.NAME, 'submit_it'))
if wait_new:
    time.sleep(1)
    item = driver.find_element(By.NAME, 'create_it')
    item.click()
    time.sleep(2)
elif wait_old:
    time.sleep(1)
    driver.refresh()
    time.sleep(2)

You need to execute the wait in a try...except statement and catch the TimeoutException should the finding of the element fail. And try to use the built in expected conditions

from selenium.webdriver.support.wait import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException

wait = WebDriverWait(driver, timeout=10)
try:
    #elem = wait.until(lambda driver: driver.find_element(By.NAME, 'create_it'))
    elem = wait.until(EC.presence_of_element_located((By.NAME, 'create_it')))
    driver.execute_script("arguments[0].scrollIntoView({behavior: 'smooth', block: 'end', inline: 'end'});", elem)
    wait.until(EC.element_to_be_clickable(elem)).click()
except TimeoutException:
    driver.refresh()

Follow same process for the submit_it element

From your code above, it seems that you're waiting for an element to be present before clicking it. For use cases like this, Selenium provides explicit waits, for instance:

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

element = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.NAME, "create_it")))

This piece of code will keep trying to locate the element every 500 ms, until it times out (10 seconds).