如何在运行该对象之前检查 system.__comobject 是否已打开?

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英文:

How to look if system.__comobject is open before I run that object?

问题

我有一个动态对象来获取Access中的system.__comobject:

dynamic app = Marshal.GetActiveObject("Access.Application");

现在我像这样打开一个表单:

app.Run("gbOpenDataEditPart", "ediQuali.170013662.Wawi");

这是有效的,它打开了来自Access的正确表单。现在我想要的是如果已经打开了,就循环执行。我想也许有一个像IsOpen这样的方法,但它没有打开。有没有另一种方法可以循环检查是否打开?

我尝试了用Powershell脚本来实现,但是窗口也不在那里:

$accessApp = [System.Runtime.InteropServices.Marshal]::GetActiveObject("Access.Application")

$forms = $accessApp.CurrentProject.AllForms

foreach ($form in $forms) {
    Write-Host "表单名称: $($form.Name)"
}

我可以看到我想要查看是否已经打开的应用程序,但是当我使用以下代码查看所有表单时:

CurrentProject.AllForms("HPGebote").IsLoaded

或者

CurrentProject.AllForms("ediQuali.170013662.Wawi").IsLoaded

然后找不到具有我正在搜索的名称的表单。

而且,无论我在我的Access中打开哪个表格:

Access截图

他总是会检测到frmSysAuskunft,而无论我打开多少个表单,他总是只检测到一个,而且名字总是相同的。

英文:

I have this dynamic Object to get the system.__comobject from Access:

   dynamic app = Marshal.GetActiveObject("Access.Application");

And now I open a form like this:

    app.Run("gbOpenDataEditPart", "ediQuali.170013662.Wawi");

and that is working. It opens the right form from Access. Now what I want is to loop if this exactly already open. I thought maybe there is a method like if(IsOpen), but it isn't open. Is there another way to loop if this is open?

And I tried it with Powershell script with that but there is the Window not there too:

$accessApp = [System.Runtime.InteropServices.Marshal]::GetActiveObject("Access.Application")

$forms = $accessApp.CurrentProject.AllForms

foreach ($form in $forms) {
    Write-Host "Form name: $($form.Name)"
}

Example1

I can see my Application which I want to look if it is already open or not but when I look through AllForms with that:

CurrentProject.AllForms("HPGebote").IsLoaded

or

CurrentProject.AllForms("ediQuali.170013662.Wawi").IsLoaded

then there is no form which has the name I am searching for.

And no matter which Formular I will open in my Access:

Access

He will always detect frmSysAuskunft and thats It no matter how many Forms I will have Open he will always just detect one with always the same name

答案1

得分: 0

你好,以下是你提供的代码的翻译:

好的,我只需添加这一行:

使用 Microsoft.VisualBasic;

然后在我的代码中可以这样做:

按钮打开表单,按钮关闭表单,以及按钮测试/检查表单是否打开。

private void button1_Click(object sender, EventArgs e)
{
    dynamic app = Interaction.GetObject(Class: "Access.Application");
    app.DoCmd.Openform("tblHotelsA");
}

private void button2_Click(object sender, EventArgs e)
{
    dynamic app = Interaction.GetObject(Class: "Access.Application");

    bool IsOpen = app.CurrentProject.AllForms("tblHotelsA").IsLoaded;
    MessageBox.Show($"表单 tblHotelsA 的状态 \n 是否打开:{IsOpen.ToString()}");
}

private void button3_Click(object sender, EventArgs e)
{
    dynamic app = Interaction.GetObject(Class: "Access.Application");
    app.DoCmd.Close(2,"tblHotelsA");
}

希望对你有所帮助!

英文:

Ok, I just add this:

using Microsoft.VisualBasic;

And now in my code I can do this:

button to open form, button to close the form, and button to test/check if form is open.

    private void button1_Click(object sender, EventArgs e)
    {
        dynamic app = Interaction.GetObject(Class: "Access.Application");
        app.DoCmd.Openform("tblHotelsA");
    }

    private void button2_Click(object sender, EventArgs e)
    {
        dynamic app = Interaction.GetObject(Class: "Access.Application");

        bool IsOpen = app.CurrentProject.AllForms("tblHotelsA").IsLoaded;
        MessageBox.Show($"Status of form tblHotelsA \n Open:{IsOpen.ToString()}");
    }

    private void button3_Click(object sender, EventArgs e)
    {
        dynamic app = Interaction.GetObject(Class: "Access.Application");
        app.DoCmd.Close(2,"tblHotelsA");

    }

So, the result is this:

如何在运行该对象之前检查 system.__comobject 是否已打开?

huangapple
  • 本文由 发表于 2023年4月17日 18:14:47
  • 转载请务必保留本文链接:https://go.coder-hub.com/76034044.html
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