How to prevent Python function from interpreting escape characters in a string?

I have a following Python code:

my_str = 'some0random'


def func(x):
    print(my_str)
    temp_str = repr(x.replace("\\", "/"))
    return temp_str

print(func(my_str))

The output of the print function inside func is some@random. Is there way to stop a function from converting \100 to @?

I know I can use a raw string in variable my_str = r'some\100random' but the problem is I use this function in our internal program and I don't have access to variable itself. I can only use Python function, which receives a parameter x from outside of its scope.

The output I want to receive is 'some/100random'.

> my_str = 'some\100random'

> Is there way to stop a function from converting \100 to @?

It does not do so.

When you do my_str = 'some\100random', the \100 is already converted to @.

If you want to do this replacement in the scenario you describe, you can either do

temp_str = repr(x.replace("@", "/100"))

or you can have a list of characters with which you do the replacement:

TO_BE_REPLACED = '@=$"'

def replace(c):
    """Replace a character with its octal representation"""
    if c in TO_BE_REPLACED:
        return '/%o' % ord(c) 
    else:
        return c

def func(x):
    # print(x)
    temp_str = repr("".join(replace(i) for i in x))
    return temp_str

my_str = 'some0random'

print(func(my_str))

But that will not bring back the original definition of that string, so it is not very useful, probably.