英文:
bashrc function -e file check is always false
问题
Bashrc函数接收一个文件名。即使我不使用变量，-e和/或-f检查始终返回false。
FILE=/var/log/nginx/$1
if [[ -e "$FILE" ]]; then
echo "存在"
else
echo "不存在"
fi
sudo awk '{print $1}' /var/log/nginx/$1 | cut -d" " -f1 | sort | uniq | wc -l
后面的awk命令运行正常，但if语句始终为false。
这仍然返回false，awk命令仍然运行正常：
FILE=/var/log/nginx/dtb_access
if [[ -e $FILE ]]; then
echo "存在"
else
echo "不存在"
fi
sudo awk '{print $1}' $FILE | cut -d" " -f1 | sort | uniq | wc -l
**更新**
views() {
set -x
file=/var/log/nginx/$1
if [[ -e "$file" ]]; then
echo "存在"
else
echo "不存在"
fi
sudo awk '{print $1}' "$file" | cut -d" " -f1 | sort | uniq | wc -l
set +x
}
```views dtb_access```的输出：
- file=/var/log/nginx/dtb_access
- [[ -e /var/log/nginx/dtb_access ]]
- echo 不存在
不存在 - wc -l
- uniq
- sort
- cut '-d ' -f1
- sudo awk '{print $1}' /var/log/nginx/dtb_access
7 - set +x
我尝试过将变量放在引号中和不放在引号中。我尝试过只使用静态字符串和没有变量，但每次结果都是一样的。
英文:
Bashrc function receives a filename. The -e and/or -f check always returns false, even if i don't use a variable.
FILE=/var/log/nginx/$1
if [[ -e "$FILE" ]]; then
echo "exists"
else
echo "not"
fi
sudo awk '{print $1}' /var/log/nginx/$1 | cut -d" " -f1 | sort | uniq | wc -l
The latter awk command works fine, but the if statement is always false.
This still returns false and the awk command still works:
FILE=/var/log/nginx/dtb_access
if [[ -e $FILE ]]; then
echo "exists"
else
echo "not"
fi
sudo awk '{print $1}' $FILE | cut -d" " -f1 | sort | uniq | wc -l
update
views() {
set -x
file=/var/log/nginx/$1
if [[ -e "$file" ]]; then
echo "exists"
else
echo "not"
fi
sudo awk '{print $1}' "$file" | cut -d" " -f1 | sort | uniq | wc -l
set +x
}
output of views dtb_access:
+ file=/var/log/nginx/dtb_access
+ [[ -e /var/log/nginx/dtb_access ]]
+ echo not
not
+ wc -l
+ uniq
+ sort
+ cut '-d ' -f1
+ sudo awk '{print $1}' /var/log/nginx/dtb_access
7
+ set +x
I've tried putting the variable in both types of quotations and none at all. I've tried just using a static string and no variable, every time it's the same outcome
答案1
得分: 2
尝试
文件="/var/log/nginx/dtb_access"
如果 sudo test -e "$文件"; then
echo "存在"
else
echo "不存在"
fi
sudo awk ...
因为运行脚本的用户可能无法访问 `/var/log/nginx`，因此 `-e` 失败。
英文:
Try
file="/var/log/nginx/dtb_access"
if sudo test -e "$file"; then
echo "exists"
else
echo "not"
fi
sudo awk ...
as the user running the script may not have access to /var/log/nginx and therefore -e fails.
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