Why this error occuring "TypeError: Series.replace() takes from 1 to 3 positional arguments but 4 were given", Where I send 3 arguments?

I want to replace a "\\N" value with "O" by pandas.

> But it's showing me this error:

df["amount_recived"].replace("\\N", "0", True)
TypeError: Series.replace() takes from 1 to 3 positional arguments but 4 were given

> My script was:

import pandas as pd
import numpy as np
# import matplotlib.pyplot as plt

df1 = pd.read_csv("C:/Users/sanyk/Downloads/SM_Data/Data_Set.csv")
df2 = pd.read_csv("C:/Users/sanyk/Downloads/SM_Data/Data_Set_2nd_part.csv")

df = pd.concat([df1, df2])

# Less Important column value manipulating
df["amount_recived"].replace("\\N", "0", True)

As you can see that there I just sent in "replace()" method "\\N" as the argument value of to_replace, "0" as "value" and regex=True. That means I didn't send anything wrong to the "replace()" method. Official Doc

Correct this by removing the True arg in your replace :

df["amount_recived"] = df["amount_recived"].replace("\\N", "0")

True is your 3rd unnecessary arg

From the documentation on function definitions:
> Parameters after “*” or “*identifier” are keyword-only parameters and may only be passed by keyword arguments.

If you look at the definition of replace in the docs:

Series.replace(to_replace=None, value=_NoDefault.no_default, *, inplace=False, limit=None, regex=False, method=_NoDefault.no_default)

You can see that the regex parameter is listed after a *, which means it must be used as a keyword parameter. So the correct form of your code is:

df["amount_recived"] = df["amount_recived"].replace("\\N", "0", regex=True)