在一个数组中如何找到相同的单词？

huangapple
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英文:

How can I find the same words in an array?

问题

我有一个需要统计数组 finalArr[] 中第一个单词数量的程序。为此，我将第一个单词分别写入数组 distArr[]。然后，我将 finalArr[] 数组的元素与 distArr[] 数组的元素进行比较。但最终结果是不正确的。例如，在 finalArr[] 中我有字符串 "qwe qwe qwe"，正确的结果应该是 "3"。

英文:

I have a program that needs to count the number of first words in an array finalArr[].
To do this, I separately write the first word to an array distArr[]. Then I compare the elements of the finalArr[] array with the elements of the distArr[] array. But final result is incorrect. For example, I have string "qwe qwe qwe" in finalArr[], and correct result must be "3".

  1. #include <stdio.h>
  2. #include <string.h>
  4. void main(void)
  5. {
  6.     char finalArr[100];
  7.     char src;
  8.     int i = 0;
  10.     printf("Enter a string: ");
  11.     // fill the array
  12.     while ((src = getchar()) != '\n' && i < 99)
  13.     {
  14.         finalArr[i] = src;
  15.         i++;
  16.     }
  17.     finalArr[i] = '
    #include <stdio.h>
  18. #include <string.h>
  19. void main(void)
  20. {
  21. char finalArr[100];
  22. char src;
  23. int i = 0;
  24. printf("Enter a string: ");
  25. // fill the array
  26. while ((src = getchar()) != '\n' && i < 99)
  27. {
  28. finalArr[i] = src;
  29. i++;
  30. }
  31. finalArr[i] = '\0';
  32. printf("Result is: %s\n", finalArr); // output array
  33. // writing first word to distArr[]
  34. char distArr[100];
  35. int j = 0;
  36. for (j = 0; j < strlen(finalArr); j++)
  37. {
  38. distArr[j] = finalArr[j];
  39. if (finalArr[j] == ' ')
  40. {
  41. break;
  42. }
  43. }
  44. distArr[j] = '\0';
  45. printf("Dist array: %s\n", distArr);
  46. printf("%c", distArr[0]);
  47. // Compare the first word with all elements of the array finalArr[]
  48. int count = 0;
  49. int d;
  50. for (int k = 0; k < strlen(finalArr); k++) {
  51. if (finalArr[k] == ' ') {
  52. k++;
  53. }
  54. for(int d = k; d < strlen(distArr); d++) {
  55. if (distArr[d] == finalArr[d]) {
  56. count++;
  57. }
  58. }
  59. }
  60. printf("Count: %d", count);
  61. }
  62. ';
  63.     printf("Result is: %s\n", finalArr); // output array
  65.     // writing first word to distArr[]
  66.     char distArr[100];
  67.     int j = 0;
  68.     for (j = 0; j < strlen(finalArr); j++)
  69.     {
  70.         distArr[j] = finalArr[j];
  71.         if (finalArr[j] == ' ')
  72.         {
  73.             break;
  74.         }
  75.     }
  76.     distArr[j] = '
    #include <stdio.h>
  77. #include <string.h>
  78. void main(void)
  79. {
  80. char finalArr[100];
  81. char src;
  82. int i = 0;
  83. printf("Enter a string: ");
  84. // fill the array
  85. while ((src = getchar()) != '\n' && i < 99)
  86. {
  87. finalArr[i] = src;
  88. i++;
  89. }
  90. finalArr[i] = '\0';
  91. printf("Result is: %s\n", finalArr); // output array
  92. // writing first word to distArr[]
  93. char distArr[100];
  94. int j = 0;
  95. for (j = 0; j < strlen(finalArr); j++)
  96. {
  97. distArr[j] = finalArr[j];
  98. if (finalArr[j] == ' ')
  99. {
  100. break;
  101. }
  102. }
  103. distArr[j] = '\0';
  104. printf("Dist array: %s\n", distArr);
  105. printf("%c", distArr[0]);
  106. // Compare the first word with all elements of the array finalArr[]
  107. int count = 0;
  108. int d;
  109. for (int k = 0; k < strlen(finalArr); k++) {
  110. if (finalArr[k] == ' ') {
  111. k++;
  112. }
  113. for(int d = k; d < strlen(distArr); d++) {
  114. if (distArr[d] == finalArr[d]) {
  115. count++;
  116. }
  117. }
  118. }
  119. printf("Count: %d", count);
  120. }
  121. ';
  122.     printf("Dist array: %s\n", distArr);
  123.     printf("%c", distArr[0]);
  125.     // Compare the first word with all elements of the array finalArr[]
  126.     int count = 0;
  127.     int d;
  128.     for (int k = 0; k < strlen(finalArr); k++) {
  129.         if (finalArr[k] == ' ') {
  130.             k++;
  131.         }
  132.         for(int d = k; d < strlen(distArr); d++) {
  133.         if (distArr[d] == finalArr[d]) {
  134.             count++;
  135.             }
  136.         }
  137.     }
  138.     printf("Count: %d", count);
  139. }

preferably, use one-dimensional arrays without strtok

答案1

得分: 0

  1. 这样的代码可能会起作用：
  3.     #include <stdio.h>
  4.     #include <string.h>
  5.     
  6.     int main() {
  7.         const char delim[] = " ";
  8.         char finalArr[] = "qwe qwe qwe";
  9.         char distArr[] = "qwe";
  10.         int count = 0;
  11.         
  12.         char *ptr = strtok(finalArr, delim);
  13.     
  14.     	while(ptr != NULL)
  15.     	{
  16.     		if (!strcmp(ptr, distArr))
  17.     		    count++; //strings match
  18.     		ptr = strtok(NULL, delim);
  19.     	}
  20.     	
  21.     	printf("Result:%d", count);
  22.     
  23.         return 0;
  24.     }
英文:

Something like this could work:

  1. #include &lt;stdio.h&gt;
  2. #include &lt;string.h&gt;
  4. int main() {
  5.     const char delim [] = &quot; &quot;;
  6.     char finalArr [] = &quot;qwe qwe qwe&quot;;
  7.     char distArr [] = &quot;qwe&quot;;
  8.     int count = 0;
  9.     
  10.     char *ptr = strtok(finalArr, delim);
  12. 	while(ptr != NULL)
  13. 	{
  14. 		if (!strcmp(ptr,distArr))
  15. 		    count++; //strings match
  16. 		ptr = strtok(NULL, delim);
  17. 	}
  18. 	
  19. 	printf(&quot;Result:%d&quot;,count);
  21.     return 0;
  22. }

This outputs:
Result:3

huangapple
  • 本文由 发表于 2023年4月13日 22:01:34
  • 转载请务必保留本文链接：https://go.coder-hub.com/76006357.html
  • arrays
  • c
  • loops
  • string
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